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The paetial pressure of ethane over a saturated solution containing 6.56×10 to the power -3g of ethane, is 1 bar. if the solution were to contains 5.0×10 to the power -2g of ethane, then what will be the partial pressure of the gas?
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The paetial pressure of ethane over a saturated solution containing 6....
Applying the Henry's Law in = kH x p In the first case, 6.56 x 10-2 g = kH x 1 bar or kH = 6.56 x 10-2 g bar-1 Put kH value in the second case 5.00 x 10-2 g = (6.56 x 10-2 g bar-1) x p 
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The paetial pressure of ethane over a saturated solution containing 6....
Understanding Partial Pressure
The partial pressure of a gas above a solution is directly related to its concentration in the solution, according to Henry's Law. This law states that the concentration of a gas dissolved in a liquid is proportional to the partial pressure of that gas above the liquid.
Initial Conditions
- Given:
- Mass of ethane (C2H6) = 6.56 × 10^-3 g
- Partial pressure = 1 bar
Calculating Molarity
1. Determine the molar mass of ethane (C2H6):
- C: 12.01 g/mol × 2 = 24.02 g/mol
- H: 1.008 g/mol × 6 = 6.048 g/mol
- Total molar mass ≈ 30.07 g/mol
2. Calculate the number of moles of ethane in 6.56 × 10^-3 g:
- Moles = mass/molar mass = (6.56 × 10^-3 g) / (30.07 g/mol) ≈ 2.18 × 10^-4 mol
Finding New Partial Pressure
- If the mass of ethane increases to 5.0 × 10^-2 g:
- Moles = (5.0 × 10^-2 g) / (30.07 g/mol) ≈ 1.66 × 10^-3 mol
- This new concentration is significantly higher. According to Henry's Law, since the concentration increases, the partial pressure must also increase proportionally.
Calculating New Partial Pressure
- Using the initial conditions:
- Initial pressure (1 bar) corresponds to initial moles (2.18 × 10^-4 mol).
- New pressure can be calculated as:
- New Pressure = (New moles / Initial moles) × Initial Pressure
- New Pressure ≈ (1.66 × 10^-3 mol / 2.18 × 10^-4 mol) × 1 bar ≈ 7.6 bar
Conclusion
- Therefore, the partial pressure of ethane when the solution contains 5.0 × 10^-2 g of ethane would be approximately 7.6 bar. This illustrates the direct relationship between solubility and gas pressure above the solution.
The partial pressure of a gas above a solution is directly related to its concentration in the solution, according to Henry's Law. This law states that the concentration of a gas dissolved in a liquid is proportional to the partial pressure of that gas above the liquid.
Initial Conditions
- Given:
- Mass of ethane (C2H6) = 6.56 × 10^-3 g
- Partial pressure = 1 bar
Calculating Molarity
1. Determine the molar mass of ethane (C2H6):
- C: 12.01 g/mol × 2 = 24.02 g/mol
- H: 1.008 g/mol × 6 = 6.048 g/mol
- Total molar mass ≈ 30.07 g/mol
2. Calculate the number of moles of ethane in 6.56 × 10^-3 g:
- Moles = mass/molar mass = (6.56 × 10^-3 g) / (30.07 g/mol) ≈ 2.18 × 10^-4 mol
Finding New Partial Pressure
- If the mass of ethane increases to 5.0 × 10^-2 g:
- Moles = (5.0 × 10^-2 g) / (30.07 g/mol) ≈ 1.66 × 10^-3 mol
- This new concentration is significantly higher. According to Henry's Law, since the concentration increases, the partial pressure must also increase proportionally.
Calculating New Partial Pressure
- Using the initial conditions:
- Initial pressure (1 bar) corresponds to initial moles (2.18 × 10^-4 mol).
- New pressure can be calculated as:
- New Pressure = (New moles / Initial moles) × Initial Pressure
- New Pressure ≈ (1.66 × 10^-3 mol / 2.18 × 10^-4 mol) × 1 bar ≈ 7.6 bar
Conclusion
- Therefore, the partial pressure of ethane when the solution contains 5.0 × 10^-2 g of ethane would be approximately 7.6 bar. This illustrates the direct relationship between solubility and gas pressure above the solution.
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The paetial pressure of ethane over a saturated solution containing 6.56×10 to the power -3g of ethane, is 1 bar. if the solution were to contains 5.0×10 to the power -2g of ethane, then what will be the partial pressure of the gas?
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The paetial pressure of ethane over a saturated solution containing 6.56×10 to the power -3g of ethane, is 1 bar. if the solution were to contains 5.0×10 to the power -2g of ethane, then what will be the partial pressure of the gas? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The paetial pressure of ethane over a saturated solution containing 6.56×10 to the power -3g of ethane, is 1 bar. if the solution were to contains 5.0×10 to the power -2g of ethane, then what will be the partial pressure of the gas? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The paetial pressure of ethane over a saturated solution containing 6.56×10 to the power -3g of ethane, is 1 bar. if the solution were to contains 5.0×10 to the power -2g of ethane, then what will be the partial pressure of the gas?.
The paetial pressure of ethane over a saturated solution containing 6.56×10 to the power -3g of ethane, is 1 bar. if the solution were to contains 5.0×10 to the power -2g of ethane, then what will be the partial pressure of the gas? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The paetial pressure of ethane over a saturated solution containing 6.56×10 to the power -3g of ethane, is 1 bar. if the solution were to contains 5.0×10 to the power -2g of ethane, then what will be the partial pressure of the gas? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The paetial pressure of ethane over a saturated solution containing 6.56×10 to the power -3g of ethane, is 1 bar. if the solution were to contains 5.0×10 to the power -2g of ethane, then what will be the partial pressure of the gas?.
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