Two moles of helium are mixed with a mole of hydrogen. The rms speed o...
Given:
- Two moles of helium (He) are mixed with one mole of hydrogen (H2).
- The root mean square (rms) speed of the gas molecules in the mixture is √2 times the speed of sound in the mixture.
To find:
The value of n.
Solution:
Step 1: Calculate the rms speed of the gas molecules:
The rms speed of a gas molecule is given by the equation: v = √(3RT/M)
Where:
- v is the rms speed
- R is the gas constant (8.314 J/(mol·K))
- T is the temperature in Kelvin
- M is the molar mass of the gas in kg/mol
In this case, we have a mixture of helium and hydrogen gases. The molar mass of helium is 4 g/mol, and the molar mass of hydrogen is 2 g/mol.
Step 2: Calculate the speed of sound in the mixture:
The speed of sound in a gas is given by the equation: v_sound = √(γRT/M)
Where:
- v_sound is the speed of sound
- γ is the adiabatic index (for diatomic gases like hydrogen, γ = 7/5)
- R is the gas constant (8.314 J/(mol·K))
- T is the temperature in Kelvin
- M is the molar mass of the gas in kg/mol
In this case, we have a mixture of helium and hydrogen gases. To find the speed of sound in the mixture, we need to calculate the average molar mass of the mixture.
Step 3: Calculate the average molar mass of the mixture:
The average molar mass of a mixture is given by the equation: M_avg = (n1M1 + n2M2) / (n1 + n2)
Where:
- M_avg is the average molar mass
- n1 and n2 are the number of moles of each gas
- M1 and M2 are the molar masses of each gas
In this case, we have two moles of helium (n1 = 2), one mole of hydrogen (n2 = 1), the molar mass of helium (M1 = 4 g/mol), and the molar mass of hydrogen (M2 = 2 g/mol). Plugging these values into the equation, we can calculate the average molar mass of the mixture.
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