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Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?
1. 1V 2. 2V 3. 0.5V 4. 0.25V?
1. 1V 2. 2V 3. 0.5V 4. 0.25V?
Most Upvoted Answer
Aconducting rod of 1m length rotating with a frequency of 50rev/sec ab...
Given:
- Length of the conducting rod, L = 1 m
- Frequency of rotation, f = 50 rev/sec
- Magnetic field, B = 6.28 mT = 6.28 × 10⁻³ T
To Find:
The value of induced emf between the ends of the rod.
Solution:
1. Calculate the Angular Velocity:
The angular velocity, ω, can be calculated using the formula:
ω = 2πf
Given that f = 50 rev/sec, we can substitute the value:
ω = 2π × 50 = 100π rad/sec
2. Calculate the Magnetic Flux:
The magnetic flux, Φ, can be calculated using the formula:
Φ = B × A
Where A is the area of the loop. In this case, the area is given by the product of the length of the rod and the width of the rod.
Given that the length of the rod, L = 1 m, we can assume that the width of the rod is negligible.
Therefore, the area, A = L × w = 1 × 0 = 0 m²
Since the area is zero, the magnetic flux, Φ, will also be zero.
3. Calculate the Induced emf:
The induced emf, ε, can be calculated using the formula:
ε = -N dΦ/dt
Where N is the number of turns in the coil and dΦ/dt is the rate of change of magnetic flux.
In this case, the rod is rotating about its end, so the number of turns, N = 1.
Since the magnetic flux, Φ, is zero, the rate of change of magnetic flux, dΦ/dt, will also be zero.
Therefore, the induced emf, ε, will be zero.
Answer:
The value of the induced emf between the ends of the rod is 0V. (Option 3)
- Length of the conducting rod, L = 1 m
- Frequency of rotation, f = 50 rev/sec
- Magnetic field, B = 6.28 mT = 6.28 × 10⁻³ T
To Find:
The value of induced emf between the ends of the rod.
Solution:
1. Calculate the Angular Velocity:
The angular velocity, ω, can be calculated using the formula:
ω = 2πf
Given that f = 50 rev/sec, we can substitute the value:
ω = 2π × 50 = 100π rad/sec
2. Calculate the Magnetic Flux:
The magnetic flux, Φ, can be calculated using the formula:
Φ = B × A
Where A is the area of the loop. In this case, the area is given by the product of the length of the rod and the width of the rod.
Given that the length of the rod, L = 1 m, we can assume that the width of the rod is negligible.
Therefore, the area, A = L × w = 1 × 0 = 0 m²
Since the area is zero, the magnetic flux, Φ, will also be zero.
3. Calculate the Induced emf:
The induced emf, ε, can be calculated using the formula:
ε = -N dΦ/dt
Where N is the number of turns in the coil and dΦ/dt is the rate of change of magnetic flux.
In this case, the rod is rotating about its end, so the number of turns, N = 1.
Since the magnetic flux, Φ, is zero, the rate of change of magnetic flux, dΦ/dt, will also be zero.
Therefore, the induced emf, ε, will be zero.
Answer:
The value of the induced emf between the ends of the rod is 0V. (Option 3)
Community Answer
Aconducting rod of 1m length rotating with a frequency of 50rev/sec ab...
.157 volt ( e= Bwl^2/2)
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Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V?
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Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V?.
Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V?.
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Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V?, a detailed solution for Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? has been provided alongside types of Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? theory, EduRev gives you an
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