All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
NEET Exam  >  NEET Questions  >  1 gram graphite on combustion in Oxygen liber... Start Learning for Free
SaveJoin the Discussion on the App
1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is?
Clear all your NEET doubts with EduRev
Verified Answer
1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amo...
Ans.
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amo...

Calculation of Heat Evolved

- Given: 1 gram of graphite liberates 7.82 kcal of heat
- We need to find the amount of heat evolved when 1 mole of oxygen is used in this oxidation process

Calculating the Heat Evolved per gram of Oxygen

- The molar mass of graphite is 12 g/mol, and the molar mass of oxygen is 32 g/mol
- Therefore, the number of moles of graphite in 1 gram = 1/12 mol
- According to the given information, 1 gram of graphite liberates 7.82 kcal of heat
- So, the heat evolved per mole of graphite = 7.82 * 12 kcal/mol

Calculating the Heat Evolved per mole of Oxygen

- In the reaction, 1 mole of graphite reacts with 1 mole of oxygen to produce carbon dioxide
- So, the heat evolved per mole of oxygen = (7.82 * 12) / 1 kcal/mol

Final Calculation

- The heat evolved when 1 mole of oxygen is used in this oxidation process = 7.82 * 12 kcal/mol
- Therefore, the amount of heat evolved when 1 mole of oxygen is used in the oxidation of 1 gram of graphite is 94.44 kcal.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Similar NEET Doubts

Read the passage given below and answer the following questions:Adenosine triphosphate (ATP) is the energy carrying molecule found in the cells of all living things. ATP captures chemical energy obtained from the breakdown of food molecules and releases it to fuel other cellular processes. ATP is a nucleotide that consists of three main structures: the nitrogenous base, adenine; the sugar, ribose; and a chain of three phosphate groups bound to ribose. The phosphate tail of ATP is the actual power source which the cell taps. Available energy is contained in the bonds between the phosphates and is released when they are broken, which occurs through the addition of a water molecule (a process called hydrolysis). Usually only the outer phosphate is removed from ATP to yield energy; when this occurs ATP is converted to adenosine diphosphate (ADP), the form of the nucleotide having only two phosphates.The importance of ATP (adenosine triphosphat e) as the main source of chemical energy in living matter and its involvement in cellular processes has long been recognized. The primary mechanism whereby higher organisms, including humans, generate ATP is through mitochondrial oxidative phosphorylation. For the majority of organs, the main metabolic fuel is glucose, which in the presence of oxygen undergoes complete combustion to CO2 and H2O: C6H12O6 + 6O2 → 6O2 + 6H2O + energyThe free energy (ΔG) liberated in this exergonic (ΔG is negative) reaction is partially trapped as ATP in two consecutive processes: glycolysis (cytosol) and oxidative phosphorylation (mitochondri

Read the passage given below and answer the following questions:Adenosine triphosphate (ATP) is the energy carrying molecule found in the cells of all living things. ATP captures chemical energy obtained from the breakdown of food molecules and releases it to fuel other cellular processes. ATP is a nucleotide that consists of three main structures: the nitrogenous base, adenine; the sugar, ribose; and a chain of three phosphate groups bound to ribose. The phosphate tail of ATP is the actual power source which the cell taps. Available energy is contained in the bonds between the phosphates and is released when they are broken, which occurs through the addition of a water molecule (a process called hydrolysis). Usually only the outer phosphate is removed from ATP to yield energy; when this occurs ATP is converted to adenosine diphosphate (ADP), the form of the nucleotide having only two phosphates.The importance of ATP (adenosine triphosphat e) as the main source of chemical energy in living matter and its involvement in cellular processes has long been recognized. The primary mechanism whereby higher organisms, including humans, generate ATP is through mitochondrial oxidative phosphorylation. For the majority of organs, the main metabolic fuel is glucose, which in the presence of oxygen undergoes complete combustion to CO2 and H2O: C6H12O6 + 6O2 → 6O2 + 6H2O + energyThe free energy (ΔG) liberated in this exergonic (ΔG is negative) reaction is partially trapped as ATP in two consecutive processes: glycolysis (cytosol) and oxidative phosphorylation (mitochondri

Top Courses for NEETView all

Top Courses for NEET

1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is?
Question Description
1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is?.
Solutions for 1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of 1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is? defined & explained in the simplest way possible. Besides giving the explanation of 1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is?, a detailed solution for 1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is? has been provided alongside types of 1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is? theory, EduRev gives you an ample number of questions to practice 1 gram graphite on combustion in Oxygen liberate 7.82kcal heat.The amount of heat Evolved when 1 mole of oxygen is used in this oxidation process is? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup