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If ionization energy of hydrogen is 313.8kcal per mole, then the energy of the electron in 2nd excited state will be a)-113.2kcal/mole b)-78.45kcal/mole c)-313.8kcal/mole d)-35kcal/mole?
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If ionization energy of hydrogen is 313.8kcal per mole, then the energ...
Calculation of Energy in 2nd Excited State of Hydrogen Atom
Ionization Energy of Hydrogen
The ionization energy of hydrogen is given as 313.8 kcal per mole.
Energy Levels of Hydrogen Atom
The energy levels of the hydrogen atom are given by the formula:
E = -13.6/n^2 eV
where n is the principal quantum number.
Energy in 2nd Excited State
The energy in the 2nd excited state can be calculated using the following formula:
E2 = -13.6/2^2 = -3.4 eV
Conversion of Energy from eV to kcal per mole
To convert the energy from eV to kcal per mole, we use the conversion factor:
1 eV = 23.06 kcal/mol
Therefore, the energy in the 2nd excited state of hydrogen atom is calculated as follows:
E2 = -3.4 eV x 23.06 kcal/mol per eV
E2 = -78.44 kcal/mol
Answer
Therefore, the energy of the electron in the 2nd excited state of hydrogen atom is -78.44 kcal/mol. Hence, the correct option is (b) -78.45 kcal/mole.
Ionization Energy of Hydrogen
The ionization energy of hydrogen is given as 313.8 kcal per mole.
Energy Levels of Hydrogen Atom
The energy levels of the hydrogen atom are given by the formula:
E = -13.6/n^2 eV
where n is the principal quantum number.
Energy in 2nd Excited State
The energy in the 2nd excited state can be calculated using the following formula:
E2 = -13.6/2^2 = -3.4 eV
Conversion of Energy from eV to kcal per mole
To convert the energy from eV to kcal per mole, we use the conversion factor:
1 eV = 23.06 kcal/mol
Therefore, the energy in the 2nd excited state of hydrogen atom is calculated as follows:
E2 = -3.4 eV x 23.06 kcal/mol per eV
E2 = -78.44 kcal/mol
Answer
Therefore, the energy of the electron in the 2nd excited state of hydrogen atom is -78.44 kcal/mol. Hence, the correct option is (b) -78.45 kcal/mole.
Community Answer
If ionization energy of hydrogen is 313.8kcal per mole, then the energ...
B) -78.45
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If ionization energy of hydrogen is 313.8kcal per mole, then the energy of the electron in 2nd excited state will be a)-113.2kcal/mole b)-78.45kcal/mole c)-313.8kcal/mole d)-35kcal/mole?
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If ionization energy of hydrogen is 313.8kcal per mole, then the energy of the electron in 2nd excited state will be a)-113.2kcal/mole b)-78.45kcal/mole c)-313.8kcal/mole d)-35kcal/mole? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If ionization energy of hydrogen is 313.8kcal per mole, then the energy of the electron in 2nd excited state will be a)-113.2kcal/mole b)-78.45kcal/mole c)-313.8kcal/mole d)-35kcal/mole? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If ionization energy of hydrogen is 313.8kcal per mole, then the energy of the electron in 2nd excited state will be a)-113.2kcal/mole b)-78.45kcal/mole c)-313.8kcal/mole d)-35kcal/mole?.
If ionization energy of hydrogen is 313.8kcal per mole, then the energy of the electron in 2nd excited state will be a)-113.2kcal/mole b)-78.45kcal/mole c)-313.8kcal/mole d)-35kcal/mole? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If ionization energy of hydrogen is 313.8kcal per mole, then the energy of the electron in 2nd excited state will be a)-113.2kcal/mole b)-78.45kcal/mole c)-313.8kcal/mole d)-35kcal/mole? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If ionization energy of hydrogen is 313.8kcal per mole, then the energy of the electron in 2nd excited state will be a)-113.2kcal/mole b)-78.45kcal/mole c)-313.8kcal/mole d)-35kcal/mole?.
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