A simple supported beam with rectangular cross section is subjected to a concentrated load at mid span. If the width and depth of beam are doubled, the deflection at mid span will be reduced to:-
  • a)
    6.25%
  • b)
    12.5%
  • c)
    50%
  • d)
    25%
Correct answer is option 'A'. Can you explain this answer?

Civil Engineering (CE) Question

Indukant
Mar 30, 2020
Max. deflection at mid span(δ)=5WL4/384EI
Hence,deflection is inversely proportional to the moment of inertia.
For rectangular section,I=bd3/12
Therefore,if width and depth both are doubled,deflection will get reduced to 6.25%.

Shailendra Singh
Feb 15, 2020
Max. deflection at mid span(δ)=5WL4/384EI
Hence,deflection is inversely proportional to the moment of inertia.
For rectangular section,I=bd3/12
Therefore,if width and depth both are doubled,deflection will get reduced to 6.25%.

Naroj Boda
Feb 13, 2020
Max. deflection at mid span(δ)=5WL4/384EI
Hence,deflection is inversely proportional to the moment of inertia.
For rectangular section,I=bd3/12
Therefore,if width and depth both are doubled,deflection will get reduced to 6.25%.

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