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A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres?
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A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb...
**Solution:**
To solve this problem, we can use the ideal gas law equation:
PV = nRT
where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
Since the temperature remains constant, we can simplify the equation to:
PV = constant
Let's analyze the situation step by step:
1. Initial conditions: The first bulb contains a gas at 1 atm pressure. The volume of this bulb (V1) is unknown.
2. Connection: The first bulb is connected to another evacuated bulb of volume 0.5 L.
3. Opening the stopcock: When the stopcock is opened, the pressure in each bulb becomes 7.58 * 10^4 Pa. Let's call this common pressure Pfinal.
Now, let's apply the ideal gas law to both bulbs before and after the stopcock is opened:
**First Bulb (Initial Conditions):**
P1 * V1 = n * R * T
**First Bulb (After Opening the Stopcock):**
Pfinal * V1 = n * R * T
**Second Bulb (After Opening the Stopcock):**
Pfinal * V2 = n * R * T
Since the number of moles and the temperature remain constant, we can equate the equations for the first and second bulbs:
Pfinal * V1 = Pfinal * V2
Now, let's substitute the values:
Pfinal = 7.58 * 10^4 Pa
V2 = 0.5 L
7.58 * 10^4 * V1 = 7.58 * 10^4 * 0.5
V1 = 0.5 L
Therefore, the volume of the first bulb (V) is 0.5 L.
In conclusion, the unknown volume of the first bulb is 0.5 L.
To solve this problem, we can use the ideal gas law equation:
PV = nRT
where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
Since the temperature remains constant, we can simplify the equation to:
PV = constant
Let's analyze the situation step by step:
1. Initial conditions: The first bulb contains a gas at 1 atm pressure. The volume of this bulb (V1) is unknown.
2. Connection: The first bulb is connected to another evacuated bulb of volume 0.5 L.
3. Opening the stopcock: When the stopcock is opened, the pressure in each bulb becomes 7.58 * 10^4 Pa. Let's call this common pressure Pfinal.
Now, let's apply the ideal gas law to both bulbs before and after the stopcock is opened:
**First Bulb (Initial Conditions):**
P1 * V1 = n * R * T
**First Bulb (After Opening the Stopcock):**
Pfinal * V1 = n * R * T
**Second Bulb (After Opening the Stopcock):**
Pfinal * V2 = n * R * T
Since the number of moles and the temperature remain constant, we can equate the equations for the first and second bulbs:
Pfinal * V1 = Pfinal * V2
Now, let's substitute the values:
Pfinal = 7.58 * 10^4 Pa
V2 = 0.5 L
7.58 * 10^4 * V1 = 7.58 * 10^4 * 0.5
V1 = 0.5 L
Therefore, the volume of the first bulb (V) is 0.5 L.
In conclusion, the unknown volume of the first bulb is 0.5 L.
Community Answer
A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb...
Boyle's law.... P1v1=p2v2
Here p1=1atm=1.013*10^5paV1=v, p2=7.58*10^5 paAnd v2=(v+0.5) litres. Substituting the value of p1, v1, p2 and v2 in the above relation. 1.013*10^5*v=7.58*10^5*(0.5+v)or
v=- 0.586 litres
Here p1=1atm=1.013*10^5paV1=v, p2=7.58*10^5 paAnd v2=(v+0.5) litres. Substituting the value of p1, v1, p2 and v2 in the above relation. 1.013*10^5*v=7.58*10^5*(0.5+v)or
v=- 0.586 litres
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A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres?
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A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres?.
A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres?.
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A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres?, a detailed solution for A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres? has been provided alongside types of A bulb of unknown volume V contains a gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5L through a stop clock. When the stop cock was opened the pressure at each bulb becomes 7.58*10^4Pa mm while the temperature remained constant. Calculate V in litres? theory, EduRev gives you an
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