Right triangle PQR is to be constructed in the xy- plane so that the r...
In order to solve this problem, we need to consider the properties of a right triangle and the given inequalities.
A right triangle has one angle equal to 90 degrees, so the right angle at point P satisfies this condition.
Line PR is parallel to the x-axis, which means that the y-coordinate of point R must be the same as the y-coordinate of point P. Let's call this y-coordinate "y".
Now, let's consider the inequalities. We are given that -4 ≤ x ≤ 3 and -3 ≤ y ≤ 5. We need to find integer coordinates that satisfy these inequalities.
Since line PR is parallel to the x-axis, the x-coordinate of point R must be the same as the x-coordinate of point Q. Let's call this x-coordinate "x".
Now, let's consider the right triangle PQR. We know that the length of line PR is equal to the difference between the x-coordinates of P and R, which is |x - x| = 0. Since line PR is parallel to the x-axis, it is a horizontal line with length 0.
The length of line PQ is equal to the difference between the y-coordinates of P and Q, which is |y - y| = 0. Since line PQ is parallel to the y-axis, it is a vertical line with length 0.
Therefore, the right triangle PQR degenerates into a single point at P, with coordinates (x, y).
In order to satisfy the given inequalities, we need to find integer values of x and y that fall within the given ranges. Since -4 ≤ x ≤ 3 and -3 ≤ y ≤ 5, we can choose any integer values for x and y that fall within these ranges. For example, we can choose x = 0 and y = 0, which satisfies the inequalities and gives us a right triangle with coordinates P(0, 0), Q(0, 0), and R(0, 0).
Therefore, the integer coordinates of P, Q, and R that satisfy the given conditions are P(0, 0), Q(0, 0), and R(0, 0).