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When an alpha particle of mass 'm' moving with velocity v bombards on a heavy nucleus of charge Ze, it's distance of closest approach from the nucleus depends on m as: A) m B) 1/m C)1/underroot of m 1/m squared?
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When an alpha particle of mass 'm' moving with velocity v bombards on ...
When an alpha particle moving with velocity v bombards on a heavy nucleus of charge Ze, then there will be no loss of energy.

Initial Kinetic energy of the alpha particle = Potential energy of alpha particle at closest approach.

That is,

rightwards double arrow space 1 half m v squared space equals space fraction numerator 2 Z e squared over denominator 4 pi epsilon subscript o r subscript o end fraction

rightwards double arrow space r subscript o space proportional to space 1 over m
This is the required distance of closest approach to alpha particle from the nucleus.
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
When an alpha particle of mass 'm' moving with velocity v bombards on ...
B)1/m....I.e.,kinetic energy=potential energy....1/2mv^2=2Ze^2/4πE• r....from this we get "r" is inversely proportional to 'm'...
Community Answer
When an alpha particle of mass 'm' moving with velocity v bombards on ...
The distance of closest approach (R) of an alpha particle to a heavy nucleus can be determined using the Rutherford scattering formula. This formula relates the impact parameter (b) to the mass (m), velocity (v), and charge (Ze) of the alpha particle, as well as the Coulomb constant (k) and the energy (E) of the alpha particle.

The Rutherford scattering formula is given by:

R = 1 / (4πε₀) * [(2Ze² / mv²) * (1 / (1 + √(1 + (2EZe / mv²))))]
where ε₀ is the permittivity of free space.

The dependence of R on the mass (m) can be analyzed by examining the term (2Ze² / mv²) in the formula.

1. Direct dependence on mass (m):
The term (2Ze² / mv²) in the formula suggests that the distance of closest approach is inversely proportional to the square of the alpha particle's mass (m). This means that as the mass of the alpha particle increases, the distance of closest approach decreases.

2. Inverse dependence on mass (m):
However, this interpretation is not entirely accurate. The term (1 / (1 + √(1 + (2EZe / mv²)))) also affects the distance of closest approach. This term involves the square root of (1 + (2EZe / mv²)).

As the mass (m) of the alpha particle increases, the denominator of the term (2EZe / mv²) becomes larger, resulting in a smaller value for the square root term. This, in turn, increases the overall value of the term (1 / (1 + √(1 + (2EZe / mv²)))), leading to a larger distance of closest approach.

Based on these considerations, we can conclude that the distance of closest approach (R) depends on the mass (m) of the alpha particle, but not in a simple linear or inverse linear manner. Therefore, none of the given options (A) m, (B) 1/m, (C) 1/√m, or (D) 1/m² accurately describe the dependence of R on m.
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When an alpha particle of mass 'm' moving with velocity v bombards on a heavy nucleus of charge Ze, it's distance of closest approach from the nucleus depends on m as: A) m B) 1/m C)1/underroot of m 1/m squared?
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