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A body of mass 2kg is drawn with a velocity of 2m/s on a horizontal table .if the coefficient of kinetic friction is 0.3 then calculate the heat produced in 5 sec. g=9.8 m /s^2 1)5. 2)10. 3)14. 4)28?
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A body of mass 2kg is drawn with a velocity of 2m/s on a horizontal ta...
Given data:
- Mass (m) = 2 kg
- Initial velocity (u) = 2 m/s
- Coefficient of kinetic friction (μ) = 0.3
- Time (t) = 5 sec
- Acceleration due to gravity (g) = 9.8 m/s^2
Calculating acceleration:
- The net force acting on the body (F_net) = m * a
- Weight of the body (W) = m * g
- Frictional force (F_friction) = μ * N, where N is the normal force
- Normal force (N) = m * g
- Therefore, F_net = W - F_friction
Calculating work done:
- Work done by the net force (W_net) = F_net * s, where s is the distance
- s = u * t + 0.5 * a * t^2
Calculating heat produced:
- Heat produced (Q) = W_net
Solution:
- Calculate acceleration using the above formulas.
- Calculate work done by the net force.
- Finally, calculate the heat produced in 5 seconds by using the formula mentioned above.
Answer:
- The heat produced in 5 seconds is 28 Joules.
Community Answer
A body of mass 2kg is drawn with a velocity of 2m/s on a horizontal ta...
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A body of mass 2kg is drawn with a velocity of 2m/s on a horizontal table .if the coefficient of kinetic friction is 0.3 then calculate the heat produced in 5 sec. g=9.8 m /s^2 1)5. 2)10. 3)14. 4)28?
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