What is the ratio of empirical formula mass to molecular formula mass ...
**Ratio of Empirical Formula Mass to Molecular Formula Mass of Benzene**
Benzene, with the chemical formula C6H6, is a cyclic compound consisting of six carbon atoms and six hydrogen atoms. Its empirical formula is CH, as it represents the simplest whole-number ratio of carbon to hydrogen atoms in the compound. The molecular formula of benzene is the actual formula of the compound, indicating the exact number of atoms present.
**Empirical Formula Mass**
The empirical formula mass is the sum of the atomic masses of all the atoms in the empirical formula. In the case of benzene, the empirical formula consists of one carbon atom (C) and one hydrogen atom (H). The atomic mass of carbon is approximately 12.01 grams/mol, and the atomic mass of hydrogen is approximately 1.01 grams/mol. Therefore, the empirical formula mass of benzene can be calculated as follows:
Empirical Formula Mass = (Atomic Mass of Carbon × Number of Carbon Atoms) + (Atomic Mass of Hydrogen × Number of Hydrogen Atoms)
Empirical Formula Mass = (12.01 g/mol × 1) + (1.01 g/mol × 1)
Empirical Formula Mass = 12.01 g/mol + 1.01 g/mol
Empirical Formula Mass = 13.02 g/mol
**Molecular Formula Mass**
The molecular formula mass is the sum of the atomic masses of all the atoms in the molecular formula. In the case of benzene, the molecular formula consists of six carbon atoms and six hydrogen atoms. Therefore, the molecular formula mass of benzene can be calculated as follows:
Molecular Formula Mass = (Atomic Mass of Carbon × Number of Carbon Atoms) + (Atomic Mass of Hydrogen × Number of Hydrogen Atoms)
Molecular Formula Mass = (12.01 g/mol × 6) + (1.01 g/mol × 6)
Molecular Formula Mass = 72.06 g/mol + 6.06 g/mol
Molecular Formula Mass = 78.12 g/mol
**Ratio Calculation**
To find the ratio of the empirical formula mass to the molecular formula mass, divide the empirical formula mass by the molecular formula mass:
Ratio = Empirical Formula Mass / Molecular Formula Mass
Ratio = 13.02 g/mol / 78.12 g/mol
Ratio ≈ 0.1666
Therefore, the ratio of the empirical formula mass to the molecular formula mass of benzene is approximately 0.1666.
What is the ratio of empirical formula mass to molecular formula mass ...
Empirical formula of benzene is CH (MASS=13)
molecular formula is C6H6(MASS=78)
RATIO=13÷78=1: 6
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