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father 's age is three times the sum of ages of his two son.after 5years,his age will be twice the sum of age of two children .find the age of father.
Most Upvoted Answer
father 's age is three times the sum of ages of his two son.after 5yea...
Let the present age of father be x years

and the present age of his two son is y and z

now according to the question

x = 3(y + z) -(1)

x = 3y + 3z

after 5 years late

x +5 = 2[(y+ 5 ) + (z + 5)]

x + 5 = 2(y + z + 10)

x + 5 = 2y + 2z + 20

x = 2y + 2z +15. -(2)

from equations (1) $ (2)

3y + 3z = 2y + 2z + 15

x + y = 15. -(4)

x = 15 - y. (3)

putting the value of x from equations (3) in equation (1) we get

15 - y = 3y + 3z

4y + 3z = 15


putting the value of eq (4) in eq (2)

we get

15 - y = 2y + 2z + 15

3y + 2z = 0. ×4. -(5)

4y + 3z = 15. ×3. (6)


12y + 8z = 0

12y + 9z = 45

on substituting


z = 45
Community Answer
father 's age is three times the sum of ages of his two son.after 5yea...
Problem Analysis:
Given information:
- Father's age is three times the sum of the ages of his two sons.
- After 5 years, his age will be twice the sum of the ages of his two children.
Let's denote:
- Father's age as F,
- First son's age as S1, and
- Second son's age as S2.

Equations:
From the first statement:
F = 3(S1 + S2) (1)
After 5 years:
F + 5 = 2((S1 + 5) + (S2 + 5))

Solution:
Substitute equation (1) into the second equation:
3(S1 + S2) + 5 = 2(S1 + S2 + 10)
3S1 + 3S2 + 5 = 2S1 + 2S2 + 20
S1 + S2 = 15 (2)
Now, substitute equation (2) back into equation (1):
F = 3(15)
F = 45
Therefore, the age of the father is 45 years.
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