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The de-Broglie wavelength associated with proton changes by 0.25% if its momentum is changed by P₀. The initial momentum was
- a)100 P₀
- b)P₀/400
- c)401 P₀
- d)P₀/100
Correct answer is option 'C'. Can you explain this answer?
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The de-Broglie wavelength associated with proton changes by 0.25% if i...
Given: The de-Broglie wavelength associated with proton changes by 0.25% if its momentum is changed by P.
To find: The initial momentum of the proton.
Formula used:
de-Broglie wavelength (λ) = h/p
Where h = Planck's constant and p = momentum of the particle.
Calculation:
Let the initial momentum of the proton be P₀.
The de-Broglie wavelength associated with the proton is λ₀ = h/P₀.
When the momentum changes by P, the new momentum becomes P₀ + P.
The new de-Broglie wavelength becomes λ₁ = h/(P₀ + P).
It is given that there is a 0.25% change in the de-Broglie wavelength.
Therefore, (λ₁ - λ₀)/λ₀ = 0.25/100.
Substituting the values of λ₀ and λ₁, we get:
(h/P₀ + P - h/P₀)/h/P₀ = 0.25/100
Simplifying the equation, we get:
P₀ = 401P
Therefore, the initial momentum of the proton is 401P.
Hence, the correct answer is option C.
To find: The initial momentum of the proton.
Formula used:
de-Broglie wavelength (λ) = h/p
Where h = Planck's constant and p = momentum of the particle.
Calculation:
Let the initial momentum of the proton be P₀.
The de-Broglie wavelength associated with the proton is λ₀ = h/P₀.
When the momentum changes by P, the new momentum becomes P₀ + P.
The new de-Broglie wavelength becomes λ₁ = h/(P₀ + P).
It is given that there is a 0.25% change in the de-Broglie wavelength.
Therefore, (λ₁ - λ₀)/λ₀ = 0.25/100.
Substituting the values of λ₀ and λ₁, we get:
(h/P₀ + P - h/P₀)/h/P₀ = 0.25/100
Simplifying the equation, we get:
P₀ = 401P
Therefore, the initial momentum of the proton is 401P.
Hence, the correct answer is option C.
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The de-Broglie wavelength associated with proton changes by 0.25% if its momentum is changed by P₀. The initial momentum wasa) 100 P₀ b) P₀/400 c) 401 P₀ d) P₀/100 Correct answer is option 'C'. Can you explain this answer?
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The de-Broglie wavelength associated with proton changes by 0.25% if its momentum is changed by P₀. The initial momentum wasa) 100 P₀ b) P₀/400 c) 401 P₀ d) P₀/100 Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The de-Broglie wavelength associated with proton changes by 0.25% if its momentum is changed by P₀. The initial momentum wasa) 100 P₀ b) P₀/400 c) 401 P₀ d) P₀/100 Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The de-Broglie wavelength associated with proton changes by 0.25% if its momentum is changed by P₀. The initial momentum wasa) 100 P₀ b) P₀/400 c) 401 P₀ d) P₀/100 Correct answer is option 'C'. Can you explain this answer?.
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