NEET Exam  >  NEET Questions  >  An electron revolving in an orbit of radius 0... Start Learning for Free
An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2?
Most Upvoted Answer
An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen...
Community Answer
An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen...
Given:
Radius of the orbit, r = 0.5 Å = 0.5 × 10^(-10) m
Revolutions per second, n = 10^16

To find:
The magnetic moment of the electron due to its orbital motion.

Solution:
The magnetic moment of a charged particle due to its orbital motion is given by the formula:
μ = e * A * n
where
μ is the magnetic moment,
e is the charge of the electron (1.6 × 10^(-19) C),
A is the area of the orbit, and
n is the number of revolutions per second.

Calculating the Area of the Orbit:
The area of a circle is given by the formula:
A = π * r^2
where
A is the area of the circle, and
r is the radius of the circle.

Substituting the given values:
A = π * (0.5 × 10^(-10))^2
A = π * (0.25 × 10^(-20))
A = (π/4) × 10^(-20) m^2

Calculating the Magnetic Moment:
Substituting the values of e, A, and n:
μ = (1.6 × 10^(-19) C) * [(π/4) × 10^(-20) m^2] * (10^16 rev/s)
μ = (1.6 × 10^(-19) C) * (π/4) * (10^(-20) m^2) * (10^16 rev/s)
μ = (1.6 × π/4) * (10^(-19 - 20 + 16)) C m^2
μ = (0.4π) * (10^(-23)) C m^2

Calculating the numerical value:
μ ≈ 1.256 × 10^(-23) C m^2

Therefore, the magnetic moment of the electron due to its orbital motion is approximately 1.256 × 10^(-23) C m^2.

Answer:
The correct option is 1) 1.256 × 10^(-23) Am^2.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2?
Question Description
An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2?.
Solutions for An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2? defined & explained in the simplest way possible. Besides giving the explanation of An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2?, a detailed solution for An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2? has been provided alongside types of An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2? theory, EduRev gives you an ample number of questions to practice An electron revolving in an orbit of radius 0.5Angstroms in a hydrogen atom executes 10^16 revolutions per second.The magnetic moment of electron due to its orbital motion will be. 1)1.256×10^-23 Am^2 2)653×10^-26 Am^2. 3)10^-3 Am^2. 4)256×10^-26 Am^2? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev