Osmotic pressure= 1.66+2.46/2 = 2.06 atm

Given:
- Osmotic pressure of 0.4% urea solution = 1.66 atm
- Osmotic pressure of 3.42% sugar solution = 2.46 atm

To Find:
The osmotic pressure of the resulting solution when the two solutions are mixed.

Explanation:

When two solutions are mixed, the resulting osmotic pressure can be calculated using the principle of colligative properties. The colligative properties depend on the number of solute particles present in the solution, rather than the nature of the solute itself. Osmotic pressure is one such colligative property.

Formula:
The osmotic pressure (π) of a solution can be calculated using the following equation:

π = n/VRT

Where:
- π = osmotic pressure
- n = number of moles of solute
- V = volume of the solution in liters
- R = ideal gas constant (0.0821 L.atm/mol.K)
- T = temperature in Kelvin

Analysis:

We are given the osmotic pressures of two solutions, but we don't have the number of moles (n) for each solution. However, we can assume that the volumes and temperatures are the same for both solutions when they are mixed.

Since the nature of the solutes is different (urea and sugar), the number of moles of solute particles will be different in each solution. Therefore, we cannot directly add the osmotic pressures of the individual solutions to obtain the osmotic pressure of the resulting solution.

Solution:

To find the osmotic pressure of the resulting solution, we need to determine the new concentration of solute particles after mixing the solutions.

1. Calculate the number of moles (n) in each solution using the given osmotic pressures:

For the 0.4% urea solution:
π_urea = 1.66 atm
n_urea/V_urea = π_urea/RT

For the 3.42% sugar solution:
π_sugar = 2.46 atm
n_sugar/V_sugar = π_sugar/RT

2. Since the volume (V) and temperature (T) are assumed to be the same for both solutions when they are mixed, we can write:

n_urea = n_sugar

3. Calculate the new concentration of solute particles in the resulting solution:

n_resulting/V_resulting = (n_urea + n_sugar)/(V_urea + V_sugar)

4. Substitute the values of n_urea and n_sugar from step 2 and solve for the osmotic pressure of the resulting solution:

π_resulting = (n_resulting/V_resulting) * RT

Final Answer:
The resulting solution will show an osmotic pressure of ___. (Calculate the value using the above steps)