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CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 produced are 5.6 gram and 4.4 M respectively by heating 12 gram of impure CaCO3 sample then the percent impurity of sample will be
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CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 prod...
Calculation of Percent Impurity in CaCO3 Sample
The calculated percent impurity in the CaCO3 sample is -0.0833%, which is negative. This indicates that there is some error in the given data or calculations. The negative percent impurity suggests that the mass of impurities is greater than the mass of the
Given Data:
- Mass of impure CaCO3 sample = 12 g
- Mass of CaO produced = 5.6 g
- Mass of CO2 produced = 4.4 g
Calculations:
- Calculate the molar mass of CaCO3
- Molar mass of Ca = 40.08 g/mol
- Molar mass of C = 12.01 g/mol
- Molar mass of 3O = 3 x 16 g/mol = 48 g/mol
- Molar mass of CaCO3 = 40.08 + 12.01 + 48 = 100.09 g/mol
- Calculate the number of moles of CaCO3 present in the sample
- Number of moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
- Number of moles of CaCO3 = 12 g / 100.09 g/mol = 0.1199 mol
- Calculate the number of moles of CaO produced
- According to the balanced chemical equation, 1 mole of CaCO3 gives 1 mole of CaO
- Number of moles of CaO produced = 0.1199 mol
- Calculate the mass of pure CaCO3 present in the sample
- Mass of pure CaCO3 = Number of moles of CaCO3 x Molar mass of CaCO3
- Mass of pure CaCO3 = 0.1199 mol x 100.09 g/mol = 12.01 g
- Calculate the mass of impurities present in the sample
- Mass of impurities = Mass of impure CaCO3 sample - Mass of pure CaCO3
- Mass of impurities = 12 g - 12.01 g = -0.01 g
- Calculate the percent impurity in the sample
- Percent impurity = (Mass of impurities / Mass of impure CaCO3 sample) x 100%
- Percent impurity = (-0.01 g / 12 g) x 100% = -0.0833%
Conclusion:
The calculated percent impurity in the CaCO3 sample is -0.0833%, which is negative. This indicates that there is some error in the given data or calculations. The negative percent impurity suggests that the mass of impurities is greater than the mass of the
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CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 prod...
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CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 produced are 5.6 gram and 4.4 M respectively by heating 12 gram of impure CaCO3 sample then the percent impurity of sample will be
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CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 produced are 5.6 gram and 4.4 M respectively by heating 12 gram of impure CaCO3 sample then the percent impurity of sample will be for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 produced are 5.6 gram and 4.4 M respectively by heating 12 gram of impure CaCO3 sample then the percent impurity of sample will be covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 produced are 5.6 gram and 4.4 M respectively by heating 12 gram of impure CaCO3 sample then the percent impurity of sample will be.
CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 produced are 5.6 gram and 4.4 M respectively by heating 12 gram of impure CaCO3 sample then the percent impurity of sample will be for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 produced are 5.6 gram and 4.4 M respectively by heating 12 gram of impure CaCO3 sample then the percent impurity of sample will be covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CaCO3 decomposes to give CaO and CO2 if the masses of CaO and CO2 produced are 5.6 gram and 4.4 M respectively by heating 12 gram of impure CaCO3 sample then the percent impurity of sample will be.
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