Find the number in the unit place in (321)321 x (325)326.a)1b)5c)6d)8e...
321 raised to 321=1 in unit digit and any number ending in 5 raised to any number has always 5 as unit digit, so 1×5=5
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Find the number in the unit place in (321)321 x (325)326.a)1b)5c)6d)8e...
321 raised to 321=1 in unit digit and any no ending in 5 raised to any no has always 5 as unit digit, so 1×5=5
Find the number in the unit place in (321)321 x (325)326.a)1b)5c)6d)8e...
Given:
Number 1: 321,321
Number 2: 325,326
To find:
The number in the unit place in the product of the given numbers.
Solution:
To find the number in the unit place in the product of two numbers, we need to multiply the numbers and then find the remainder when divided by 10.
Step 1: Multiply the numbers
321,321 x 325,326 = 104,543,651,346
Step 2: Find the remainder when divided by 10
104,543,651,346 % 10 = 6
Therefore, the number in the unit place in (321)321 x (325)326 is 6.