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A body starts with initial velocity 30m/s and a retardation of 4m/square. Find distance travelled by the body in 8th second.?
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Problem:

A body starts with initial velocity 30m/s and a retardation of 4m/square. Find distance travelled by the body in 8th second.


Solution:

Given, initial velocity (u) = 30m/s

Retardation (a) = -4m/square (negative sign indicates retardation)

Time taken (t) = 8s

Let's use the equation of motion:

s = ut + 1/2 at^2


  • s = distance travelled by the body

  • u = initial velocity

  • t = time taken

  • a = retardation


Substituting the given values:

s = (30 x 8) + 1/2 (-4) (8)^2

s = 240 - 128

s = 112m


Answer:

The distance travelled by the body in the 8th second is 112m.
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A body starts with initial velocity 30m/s and a retardation of 4m/square. Find distance travelled by the body in 8th second.?
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