A large tanker can be filled by two pipes A and B in 60 minutes and 40...
A = 60 2 120
B = 40 3 120
Suppose it will take x minute
3x/2 + 5x/2 = 120
8x=240
x = 30 min
View all questions of this testA large tanker can be filled by two pipes A and B in 60 minutes and 40...
Given data:
Pipe A fills the tanker in 60 minutes.
Pipe B fills the tanker in 40 minutes.
Approach:
Let the total capacity of the tanker be 120 units (LCM of 60 and 40).
Pipe A fills 2 units per minute.
Pipe B fills 3 units per minute.
Let pipe B be used for x minutes and both pipes A and B be used for (120-x) minutes.
Calculation:
According to the question,
(2x) + (3(120-x)) = 120
=> 2x + 360 - 3x = 120
=> -x = -240
=> x = 240/2
=> x = 120
Therefore, pipe B is used for 120 minutes and pipes A and B are used for (120-120) = 0 minutes.
Thus, the total time taken to fill the tanker is 120 minutes or 2 hours.
Answer:
Hence, the correct answer is option D, 30 minutes which is not correct. The correct answer is 120 minutes or 2 hours.