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A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?

  • a)
    15 min
  • b)
    20 min
  • c)
    27.5 min
  • d)
    30 min
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A large tanker can be filled by two pipes A and B in 60 minutes and 40...
A = 60 2 120
B = 40 3 120
Suppose it will take x minute
3x/2 + 5x/2 = 120
8x=240
x = 30 min
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Most Upvoted Answer
A large tanker can be filled by two pipes A and B in 60 minutes and 40...
Given data:
Pipe A fills the tanker in 60 minutes.
Pipe B fills the tanker in 40 minutes.

Approach:
Let the total capacity of the tanker be 120 units (LCM of 60 and 40).
Pipe A fills 2 units per minute.
Pipe B fills 3 units per minute.
Let pipe B be used for x minutes and both pipes A and B be used for (120-x) minutes.

Calculation:
According to the question,
(2x) + (3(120-x)) = 120
=> 2x + 360 - 3x = 120
=> -x = -240
=> x = 240/2
=> x = 120

Therefore, pipe B is used for 120 minutes and pipes A and B are used for (120-120) = 0 minutes.

Thus, the total time taken to fill the tanker is 120 minutes or 2 hours.

Answer:
Hence, the correct answer is option D, 30 minutes which is not correct. The correct answer is 120 minutes or 2 hours.
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A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half? a)15 minb)20 minc)27.5 mind)30 minCorrect answer is option 'D'. Can you explain this answer?
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