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PH of a solution obtained by mixing equal volume of 0.2M NaOH & 0.2 M CH3CooH (ka=10to the power -5)?
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And 0.2M HCl

To find the pH of the solution obtained by mixing equal volumes of 0.2M NaOH and 0.2M HCl, we need to first determine the moles of each compound.

Moles of NaOH = M x V = 0.2 x 0.5 = 0.1 mol

Moles of HCl = M x V = 0.2 x 0.5 = 0.1 mol

Since NaOH and HCl react in a 1:1 ratio, the moles of the limiting reactant (in this case, HCl) will be completely consumed, and the excess NaOH will determine the pH of the resulting solution.

The excess moles of NaOH = 0.1 - 0.1 = 0 mol

Therefore, the resulting solution will contain only NaCl and water (since NaCl is a neutral salt). The pH of the solution will be 7 (neutral).
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PH of a solution obtained by mixing equal volume of 0.2M NaOH & 0.2 M CH3CooH (ka=10to the power -5)?
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PH of a solution obtained by mixing equal volume of 0.2M NaOH & 0.2 M CH3CooH (ka=10to the power -5)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about PH of a solution obtained by mixing equal volume of 0.2M NaOH & 0.2 M CH3CooH (ka=10to the power -5)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PH of a solution obtained by mixing equal volume of 0.2M NaOH & 0.2 M CH3CooH (ka=10to the power -5)?.
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