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Equal mass of oxygen hydrogen and methane are taken in a container in identical conditions.What is the ratio of their moles?
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Ratio of Moles of Oxygen, Hydrogen, and Methane in a Container


When equal masses of oxygen, hydrogen, and methane are taken in a container in identical conditions, the ratio of their moles can be calculated using the following steps:


Step 1: Determine the Molar Masses of Each Gas



  • The molar mass of oxygen (O2) is 32 g/mol.

  • The molar mass of hydrogen (H2) is 2 g/mol.

  • The molar mass of methane (CH4) is 16 g/mol.



Step 2: Calculate the Number of Moles of Each Gas



  • To calculate the number of moles of each gas, divide the mass of each gas by its molar mass.

  • Assuming equal masses of each gas, let's say we have 1 gram of each gas.

  • The number of moles of oxygen = 1 g ÷ 32 g/mol = 0.03125 mol

  • The number of moles of hydrogen = 1 g ÷ 2 g/mol = 0.5 mol

  • The number of moles of methane = 1 g ÷ 16 g/mol = 0.0625 mol



Step 3: Determine the Ratio of Moles



  • The ratio of moles of oxygen to hydrogen to methane is 0.03125 mol : 0.5 mol : 0.0625 mol.

  • However, we can simplify this ratio by dividing each number of moles by the smallest number of moles (0.03125 mol) to get a ratio of 1:16:2.

  • Therefore, the ratio of moles of oxygen to hydrogen to methane is 1:16:2.



Therefore, when equal masses of oxygen, hydrogen, and methane are taken in a container in identical conditions, the ratio of their moles is 1:16:2.
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