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If y = 5x2 + 3, then the tangent at x = 0, y = 3
- a)passes through x = 0, y = 0
- b)has a slope of +1
- c)is parallel to the x-axis
- d)has a slope of −1
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If y = 5x2 + 3, then the tangent at x = 0, y = 3a)passes through x = 0...
The equation of the tangent line at x = 0, y = 3 can be found by taking the derivative of y = 5x^2 + 3 with respect to x and evaluating it at x = 0.
Taking the derivative, we get:
dy/dx = 10x
Evaluating at x = 0, we get:
dy/dx = 10(0) = 0
Since the slope of the tangent line is 0, we can conclude that the tangent line is parallel to the x-axis.
Therefore, the correct answer is c) is parallel to the x-axis.
Taking the derivative, we get:
dy/dx = 10x
Evaluating at x = 0, we get:
dy/dx = 10(0) = 0
Since the slope of the tangent line is 0, we can conclude that the tangent line is parallel to the x-axis.
Therefore, the correct answer is c) is parallel to the x-axis.
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If y = 5x2 + 3, then the tangent at x = 0, y = 3a)passes through x = 0, y = 0b)has a slope of +1c)is parallel to the x-axisd)has a slope of −1Correct answer is option 'C'. Can you explain this answer?
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