NEET Exam > NEET Questions > Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, mol...
Start Learning for Free
Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7?
Most Upvoted Answer
Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 ...
Community Answer
Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 ...
Molar solubility is defined as the number of moles of a substance that can be dissolved in one liter of a solution. In order to determine the molar solubility of Ni(OH)2 in 0.01M NaOH, we need to consider the solubility product constant (Ksp) of Ni(OH)2.
The Ksp expression for the dissolution of Ni(OH)2 can be written as follows:
Ni(OH)2(s) ⇌ Ni2+(aq) + 2OH-(aq)
The Ksp expression is given by the product of the concentrations of the ions raised to the power of their stoichiometric coefficients:
Ksp = [Ni2+][OH-]^2
Given that the Ksp of Ni(OH)2 is 2 x 10^-15, we can set up an equilibrium expression as follows:
2 x 10^-15 = [Ni2+][OH-]^2
Since we are considering the dissolution of Ni(OH)2 in 0.01M NaOH, we can assume that the concentration of OH- is 0.01M. This is because NaOH is a strong base and dissociates completely in water to produce OH- ions.
Substituting the concentration of OH- into the Ksp expression, we get:
2 x 10^-15 = [Ni2+](0.01)^2
Simplifying the equation, we find:
[Ni2+] = (2 x 10^-15)/(0.01)^2 = 2 x 10^-11 M
Therefore, the molar solubility of Ni(OH)2 in 0.01M NaOH is 2 x 10^-11 M.
In conclusion, the correct answer is C) 2 x 10^-11.
The Ksp expression for the dissolution of Ni(OH)2 can be written as follows:
Ni(OH)2(s) ⇌ Ni2+(aq) + 2OH-(aq)
The Ksp expression is given by the product of the concentrations of the ions raised to the power of their stoichiometric coefficients:
Ksp = [Ni2+][OH-]^2
Given that the Ksp of Ni(OH)2 is 2 x 10^-15, we can set up an equilibrium expression as follows:
2 x 10^-15 = [Ni2+][OH-]^2
Since we are considering the dissolution of Ni(OH)2 in 0.01M NaOH, we can assume that the concentration of OH- is 0.01M. This is because NaOH is a strong base and dissociates completely in water to produce OH- ions.
Substituting the concentration of OH- into the Ksp expression, we get:
2 x 10^-15 = [Ni2+](0.01)^2
Simplifying the equation, we find:
[Ni2+] = (2 x 10^-15)/(0.01)^2 = 2 x 10^-11 M
Therefore, the molar solubility of Ni(OH)2 in 0.01M NaOH is 2 x 10^-11 M.
In conclusion, the correct answer is C) 2 x 10^-11.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7?
Question Description
Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7?.
Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7?.
Solutions for Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7? defined & explained in the simplest way possible. Besides giving the explanation of
Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7?, a detailed solution for Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7? has been provided alongside types of Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7? theory, EduRev gives you an
ample number of questions to practice Ksp of a salt Ni(OH)2 is 2 x 10^-15 then, molar solubility of Ni(OH)2 in 0.01M NaOH is A) 2 x 10^-15 B) 2 x 10^-5 C) 2 x 10^-11 D) 10^-7? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup