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The ionization energy of hydrogen atom is 13.6 Ev.The energy of the ground level in doubly ionized Lithium is- 1)-28.7 ev 2)-54.4 3)-122.4?
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Calculation of Energy of Ground Level in Doubly Ionized Lithium

To calculate the energy of the ground level in doubly ionized Lithium, we need to use the formula:

E = -Z2 (13.6 eV)

where E is the energy of the ground state, Z is the atomic number of the element, and 13.6 eV is the ionization energy of hydrogen atom.

Step 1: Calculate the Atomic Number of Doubly Ionized Lithium

Lithium is a three-electron atom. When it is doubly ionized, it loses two electrons and becomes a one-electron atom. Therefore, the atomic number of doubly ionized lithium is:

Z = 3 - 2 = 1

Step 2: Calculate the Energy of the Ground State

Using the formula above, we can calculate the energy of the ground state of doubly ionized lithium:

E = -12 (13.6 eV) = -13.6 eV

However, this is the energy of the ground state of singly ionized lithium. For doubly ionized lithium, we need to subtract another 13.6 eV, since it has lost two electrons.

E = -22 (13.6 eV) = -54.4 eV

Therefore, the energy of the ground level in doubly ionized Lithium is -54.4 eV.

Conclusion

The energy of the ground level in doubly ionized Lithium is -54.4 eV. This is calculated using the formula E = -Z2 (13.6 eV), where Z is the atomic number of the element and 13.6 eV is the ionization energy of hydrogen atom.
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The ionization energy of hydrogen atom is 13.6 Ev.The energy of the ground level in doubly ionized Lithium is- 1)-28.7 ev 2)-54.4 3)-122.4?
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