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The potential energy of a charged parallel plate capacitor is U . If a slab of dielectric constant K is inserted between the plates , the new potential energy will be : a) U/K b) UK c) U d) none of these.?
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The potential energy of a charged parallel plate capacitor is U . If a...
Explanation:
When a dielectric material is inserted between the plates of a parallel plate capacitor, the capacitance of the capacitor increases by a factor of K, where K is the dielectric constant of the material. This is because the electric field inside the dielectric is reduced by a factor of K compared to the electric field in vacuum, and hence the charge density on the plates is also reduced.
Calculation of Potential Energy:
The potential energy of a capacitor is given by the formula:
U = (1/2) * C * V^2
where C is the capacitance of the capacitor and V is the potential difference between the plates.
When a dielectric material of constant K is inserted between the plates, the capacitance of the capacitor increases by a factor of K. Therefore, the new capacitance is:
C' = K * C
The potential difference between the plates remains the same, as the charge on the plates does not change. Therefore, the new potential energy of the capacitor is:
U' = (1/2) * C' * V^2
= (1/2) * K * C * V^2
= K * (1/2) * C * V^2
= K * U
Therefore, the new potential energy of the capacitor is K times the original potential energy.
Answer:
The correct option is (b) UK.
When a dielectric material is inserted between the plates of a parallel plate capacitor, the capacitance of the capacitor increases by a factor of K, where K is the dielectric constant of the material. This is because the electric field inside the dielectric is reduced by a factor of K compared to the electric field in vacuum, and hence the charge density on the plates is also reduced.
Calculation of Potential Energy:
The potential energy of a capacitor is given by the formula:
U = (1/2) * C * V^2
where C is the capacitance of the capacitor and V is the potential difference between the plates.
When a dielectric material of constant K is inserted between the plates, the capacitance of the capacitor increases by a factor of K. Therefore, the new capacitance is:
C' = K * C
The potential difference between the plates remains the same, as the charge on the plates does not change. Therefore, the new potential energy of the capacitor is:
U' = (1/2) * C' * V^2
= (1/2) * K * C * V^2
= K * (1/2) * C * V^2
= K * U
Therefore, the new potential energy of the capacitor is K times the original potential energy.
Answer:
The correct option is (b) UK.
Community Answer
The potential energy of a charged parallel plate capacitor is U . If a...
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The potential energy of a charged parallel plate capacitor is U . If a slab of dielectric constant K is inserted between the plates , the new potential energy will be : a) U/K b) UK c) U d) none of these.?
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The potential energy of a charged parallel plate capacitor is U . If a slab of dielectric constant K is inserted between the plates , the new potential energy will be : a) U/K b) UK c) U d) none of these.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The potential energy of a charged parallel plate capacitor is U . If a slab of dielectric constant K is inserted between the plates , the new potential energy will be : a) U/K b) UK c) U d) none of these.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The potential energy of a charged parallel plate capacitor is U . If a slab of dielectric constant K is inserted between the plates , the new potential energy will be : a) U/K b) UK c) U d) none of these.?.
The potential energy of a charged parallel plate capacitor is U . If a slab of dielectric constant K is inserted between the plates , the new potential energy will be : a) U/K b) UK c) U d) none of these.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The potential energy of a charged parallel plate capacitor is U . If a slab of dielectric constant K is inserted between the plates , the new potential energy will be : a) U/K b) UK c) U d) none of these.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The potential energy of a charged parallel plate capacitor is U . If a slab of dielectric constant K is inserted between the plates , the new potential energy will be : a) U/K b) UK c) U d) none of these.?.
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