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A block of mass 20 kg is kept on horizontal aurface where coefficient of friction between block and surface is 0.75.this block is connected by ideal string with another block of mass m2.the string is passing over ideal fixed pulley and m2 is vertical.what is minimum value of mass m2 which can make m1 just move on surface?
Most Upvoted Answer
A block of mass 20 kg is kept on horizontal aurface where coefficient ...
**Solution:**
To find the minimum value of mass m2 that can make m1 just move on the surface, we need to consider the forces acting on m1 and m2.
**Forces acting on m1:**
1. Weight (W1) acting vertically downwards with a magnitude of m1 * g, where g is the acceleration due to gravity.
2. Normal force (N) exerted by the horizontal surface on m1, which is equal to the weight of m1 as there is no vertical acceleration.
3. Frictional force (F) opposing the motion of m1, which is given by the equation F = μ * N, where μ is the coefficient of friction.
**Forces acting on m2:**
1. Weight (W2) acting vertically downwards with a magnitude of m2 * g.
2. Tension (T) in the string, which is the same for both m1 and m2 due to the ideal pulley.
Since m1 is at the verge of moving, the frictional force F is at its maximum value, which is equal to the limiting friction force. Therefore, the equation for the maximum frictional force is F = μ * N.
**Calculating the normal force:**
The normal force N is equal to the weight of m1, which is m1 * g.
**Substituting the values into the equation for maximum frictional force:**
F = μ * N
F = μ * m1 * g
**Calculating the tension in the string:**
Since m1 and m2 are connected by an ideal string passing over a fixed pulley, the tension in the string is the same for both blocks. Therefore, the tension T is equal to the weight of m2, which is m2 * g.
**Equating the maximum frictional force to the tension:**
μ * m1 * g = m2 * g
**Simplifying the equation:**
μ * m1 = m2
**Substituting the given coefficient of friction:**
0.75 * m1 = m2
Therefore, the minimum value of mass m2 that can make m1 just move on the surface is 0.75 times the mass of m1.
To find the minimum value of mass m2 that can make m1 just move on the surface, we need to consider the forces acting on m1 and m2.
**Forces acting on m1:**
1. Weight (W1) acting vertically downwards with a magnitude of m1 * g, where g is the acceleration due to gravity.
2. Normal force (N) exerted by the horizontal surface on m1, which is equal to the weight of m1 as there is no vertical acceleration.
3. Frictional force (F) opposing the motion of m1, which is given by the equation F = μ * N, where μ is the coefficient of friction.
**Forces acting on m2:**
1. Weight (W2) acting vertically downwards with a magnitude of m2 * g.
2. Tension (T) in the string, which is the same for both m1 and m2 due to the ideal pulley.
Since m1 is at the verge of moving, the frictional force F is at its maximum value, which is equal to the limiting friction force. Therefore, the equation for the maximum frictional force is F = μ * N.
**Calculating the normal force:**
The normal force N is equal to the weight of m1, which is m1 * g.
**Substituting the values into the equation for maximum frictional force:**
F = μ * N
F = μ * m1 * g
**Calculating the tension in the string:**
Since m1 and m2 are connected by an ideal string passing over a fixed pulley, the tension in the string is the same for both blocks. Therefore, the tension T is equal to the weight of m2, which is m2 * g.
**Equating the maximum frictional force to the tension:**
μ * m1 * g = m2 * g
**Simplifying the equation:**
μ * m1 = m2
**Substituting the given coefficient of friction:**
0.75 * m1 = m2
Therefore, the minimum value of mass m2 that can make m1 just move on the surface is 0.75 times the mass of m1.
Community Answer
A block of mass 20 kg is kept on horizontal aurface where coefficient ...
Tension in the string=m2g
thus,equation of motion for block m1 will be
nm1g=T
where, n=coefficient of friction
and T=tension=m2g
on putting the values m2 comes out to be 15kg
thus,equation of motion for block m1 will be
nm1g=T
where, n=coefficient of friction
and T=tension=m2g
on putting the values m2 comes out to be 15kg
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A block of mass 20 kg is kept on horizontal aurface where coefficient of friction between block and surface is 0.75.this block is connected by ideal string with another block of mass m2.the string is passing over ideal fixed pulley and m2 is vertical.what is minimum value of mass m2 which can make m1 just move on surface?
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A block of mass 20 kg is kept on horizontal aurface where coefficient of friction between block and surface is 0.75.this block is connected by ideal string with another block of mass m2.the string is passing over ideal fixed pulley and m2 is vertical.what is minimum value of mass m2 which can make m1 just move on surface? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A block of mass 20 kg is kept on horizontal aurface where coefficient of friction between block and surface is 0.75.this block is connected by ideal string with another block of mass m2.the string is passing over ideal fixed pulley and m2 is vertical.what is minimum value of mass m2 which can make m1 just move on surface? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 20 kg is kept on horizontal aurface where coefficient of friction between block and surface is 0.75.this block is connected by ideal string with another block of mass m2.the string is passing over ideal fixed pulley and m2 is vertical.what is minimum value of mass m2 which can make m1 just move on surface?.
A block of mass 20 kg is kept on horizontal aurface where coefficient of friction between block and surface is 0.75.this block is connected by ideal string with another block of mass m2.the string is passing over ideal fixed pulley and m2 is vertical.what is minimum value of mass m2 which can make m1 just move on surface? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A block of mass 20 kg is kept on horizontal aurface where coefficient of friction between block and surface is 0.75.this block is connected by ideal string with another block of mass m2.the string is passing over ideal fixed pulley and m2 is vertical.what is minimum value of mass m2 which can make m1 just move on surface? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 20 kg is kept on horizontal aurface where coefficient of friction between block and surface is 0.75.this block is connected by ideal string with another block of mass m2.the string is passing over ideal fixed pulley and m2 is vertical.what is minimum value of mass m2 which can make m1 just move on surface?.
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