In order to prepare one litre normal solution of KMnO4, how many grams of KMnO4 are required if the solution is to be used in acid medium for oxidation ?

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Calculating the Amount of KMnO4 Required for a 1 Litre Normal Solution

To prepare a 1 litre normal solution of KMnO4 for use in an acid medium for oxidation, the following steps can be taken:

Determine the Equivalent Weight of KMnO4:
- The molecular weight of KMnO4 is 158.034 g/mol.
- Since KMnO4 can donate one mole of oxygen atoms in an acidic medium, its equivalent weight is equal to its molecular weight divided by the number of moles of oxygen atoms it can donate, which is 5.
- Therefore, the equivalent weight of KMnO4 is 31.6068 g/mol.

Calculate the Normality of the Solution:
- Normality is defined as the number of equivalents of a substance present in a liter of solution.
- For a normal solution, the normality is 1N.
- Since the equivalent weight of KMnO4 is 31.6068 g/mol, 1N of KMnO4 solution would contain 31.6068 g of KMnO4 in 1 liter of solution.

Determine the Amount of KMnO4 Required:
- To prepare a 1N KMnO4 solution in 1 liter, you would need 31.6068 g of KMnO4.
- Therefore, you would need 31.6068 grams of KMnO4 to prepare a 1 litre normal solution for use in an acid medium for oxidation.

By following these steps and calculations, you can accurately determine the amount of KMnO4 required to prepare a 1 litre normal solution for your experiment.

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