NEET Exam > NEET Questions > 1.0 g of pure calcium carbonate was found to ...
Start Learning for Free
1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given by
- a)4 N
- b)2 N
- c)0.4 N
- d)0.2 N
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
1.0 g of pure calcium carbonate was found to require 50 ml of dilute H...
Calculation of the strength of HCl solution
Given data:
Mass of calcium carbonate = 1.0 g
Volume of HCl used = 50 ml
Step 1: Calculation of the moles of calcium carbonate
Moles = Mass/Molar mass
Molar mass of calcium carbonate = 100.08 g/mol
Moles of calcium carbonate = 1.0/100.08 = 0.00999 mol
Step 2: Calculation of the moles of HCl used
Moles of HCl = Molarity × Volume (in liters)
Volume of HCl used = 50 ml = 0.05 L
Let the molarity of HCl be 'x'
Moles of HCl = x × 0.05
Step 3: Calculation of the molarity of HCl solution
The balanced chemical equation for the reaction between calcium carbonate and HCl is:
CaCO3 + 2HCl → CaCl2 + H2O + CO2
From the equation, it is clear that 1 mole of calcium carbonate reacts with 2 moles of HCl. Therefore,
Moles of HCl used = 2 × Moles of calcium carbonate
x × 0.05 = 2 × 0.00999
x = (2 × 0.00999)/0.05
x = 0.3996 M
Step 4: Conversion of molarity to normality
Normality = Molarity × Basicity
For HCl, Basicity = 1 (as it donates 1 H+ ion)
Therefore, Normality = Molarity × 1
Normality = 0.3996 N
Hence, the strength of HCl solution is 0.4 N.
Given data:
Mass of calcium carbonate = 1.0 g
Volume of HCl used = 50 ml
Step 1: Calculation of the moles of calcium carbonate
Moles = Mass/Molar mass
Molar mass of calcium carbonate = 100.08 g/mol
Moles of calcium carbonate = 1.0/100.08 = 0.00999 mol
Step 2: Calculation of the moles of HCl used
Moles of HCl = Molarity × Volume (in liters)
Volume of HCl used = 50 ml = 0.05 L
Let the molarity of HCl be 'x'
Moles of HCl = x × 0.05
Step 3: Calculation of the molarity of HCl solution
The balanced chemical equation for the reaction between calcium carbonate and HCl is:
CaCO3 + 2HCl → CaCl2 + H2O + CO2
From the equation, it is clear that 1 mole of calcium carbonate reacts with 2 moles of HCl. Therefore,
Moles of HCl used = 2 × Moles of calcium carbonate
x × 0.05 = 2 × 0.00999
x = (2 × 0.00999)/0.05
x = 0.3996 M
Step 4: Conversion of molarity to normality
Normality = Molarity × Basicity
For HCl, Basicity = 1 (as it donates 1 H+ ion)
Therefore, Normality = Molarity × 1
Normality = 0.3996 N
Hence, the strength of HCl solution is 0.4 N.
Free Test
FREE
| Start Free Test |
Community Answer
1.0 g of pure calcium carbonate was found to require 50 ml of dilute H...
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer?
Question Description
1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer?.
1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer?.
Solutions for 1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of 1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for 1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of 1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 1.0 g of pure calcium carbonate was found to require 50 ml of dilute HCl for complete reaction. The strength of HCl solution is given bya)4 Nb)2 Nc)0.4 Nd)0.2 NCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup