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In Phosphorus atom find out the number of paired electrons for l=1 and m=0 1)3 2)4 3)2?
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In Phosphorus atom find out the number of paired electrons for l=1 and...
Number of Paired Electrons for l=1 and m=0 in Phosphorus Atom


Phosphorus is an element with atomic number 15 and electronic configuration 1s²2s²2p⁶3s²3p³. The valence shell of phosphorus has three electrons in the 3p subshell. The quantum numbers that determine the properties of these electrons are n=3, l=1, and m=-1, 0, +1. Here, we need to find the number of paired electrons for l=1 and m=0.


Quantum Numbers and Electron Pairing


The quantum numbers n, l, m, and s are used to describe the properties of electrons in an atom. The principal quantum number (n) describes the energy level of the electron, and it can have any positive integer value. The angular momentum quantum number (l) describes the shape of the electron's orbital, and it can have any integer value from 0 to n-1. The magnetic quantum number (m) describes the orientation of the electron's orbital in space, and it can have any integer value from -l to +l. The spin quantum number (s) describes the intrinsic angular momentum of the electron, and it can have two possible values: +1/2 or -1/2.


In an atom, electrons are paired up in orbitals according to Hund's rule, which states that electrons fill orbitals of the same energy level one by one, with their spins parallel, before pairing up with electrons of opposite spin in the same orbital. This is because electrons in parallel orbitals experience less repulsion than electrons in the same orbital with opposite spins.


Calculation of Paired Electrons for l=1 and m=0


The value of l=1 corresponds to the p subshell, which has three orbitals: px, py, and pz. The value of m=0 corresponds to the pz orbital, which has a lobed shape along the z-axis. In the case of phosphorus, there are three electrons in the 3p subshell, which means that they occupy three different orbitals: one in the px orbital, one in the py orbital, and one in the pz orbital.


Since we are looking for the number of paired electrons for l=1 and m=0, we only need to consider the pz orbital. According to Hund's rule, the electron in the pz orbital should have a parallel spin with the electron in the px orbital and the electron in the py orbital. Therefore, there is only one paired electron for l=1 and m=0 in phosphorus, which corresponds to the electron in the pz orbital with a parallel spin to the other two electrons in the 3p subshell.


Conclusion


The number of paired electrons for l=1 and m=0 in the phosphorus atom is 1. This corresponds to the electron in the pz orbital with a parallel spin to the other two electrons in the 3p subshell.
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In Phosphorus atom find out the number of paired electrons for l=1 and...
2 electron
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In Phosphorus atom find out the number of paired electrons for l=1 and m=0 1)3 2)4 3)2?
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