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The heat of neutralisation of strong base and strong acid is 57.0 kJ. The heat released when 0.5 mole of HNO3 , solution is added to 0.20 mole of NaOH solution is :a)57.0 kJb)11.40 kJc)28.5 kJd)34.9 kJCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The heat of neutralisation of strong base and strong acid is 57.0 kJ. The heat released when 0.5 mole of HNO3 , solution is added to 0.20 mole of NaOH solution is :a)57.0 kJb)11.40 kJc)28.5 kJd)34.9 kJCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The heat of neutralisation of strong base and strong acid is 57.0 kJ. The heat released when 0.5 mole of HNO3 , solution is added to 0.20 mole of NaOH solution is :a)57.0 kJb)11.40 kJc)28.5 kJd)34.9 kJCorrect answer is option 'B'. Can you explain this answer?.

Solutions for The heat of neutralisation of strong base and strong acid is 57.0 kJ. The heat released when 0.5 mole of HNO3 , solution is added to 0.20 mole of NaOH solution is :a)57.0 kJb)11.40 kJc)28.5 kJd)34.9 kJCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of The heat of neutralisation of strong base and strong acid is 57.0 kJ. The heat released when 0.5 mole of HNO3 , solution is added to 0.20 mole of NaOH solution is :a)57.0 kJb)11.40 kJc)28.5 kJd)34.9 kJCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The heat of neutralisation of strong base and strong acid is 57.0 kJ. The heat released when 0.5 mole of HNO3 , solution is added to 0.20 mole of NaOH solution is :a)57.0 kJb)11.40 kJc)28.5 kJd)34.9 kJCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The heat of neutralisation of strong base and strong acid is 57.0 kJ. The heat released when 0.5 mole of HNO3 , solution is added to 0.20 mole of NaOH solution is :a)57.0 kJb)11.40 kJc)28.5 kJd)34.9 kJCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The heat of neutralisation of strong base and strong acid is 57.0 kJ. The heat released when 0.5 mole of HNO3 , solution is added to 0.20 mole of NaOH solution is :a)57.0 kJb)11.40 kJc)28.5 kJd)34.9 kJCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The heat of neutralisation of strong base and strong acid is 57.0 kJ. The heat released when 0.5 mole of HNO3 , solution is added to 0.20 mole of NaOH solution is :a)57.0 kJb)11.40 kJc)28.5 kJd)34.9 kJCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.