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Two springs have force constant K1 and K2, (K1>K2). Each spring is extended by same force F. If their elastic potential energy is E1 and E2, then E1/E2 is A) K1/K2 B) K2/K2 C) √(K1/K2) D) √(K2/K1)?
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Two springs have force constant K1 and K2, (K1>K2). Each spring is ext...
Solution:

Given:

Force constant of spring 1 is K1

Force constant of spring 2 is K2

K1 > K2

Both springs are extended by the same force F

Elastic potential energy of spring 1 is E1

Elastic potential energy of spring 2 is E2


To find:

E1/E2 = ?


Explanation:

The elastic potential energy of a spring is given by,

E = (1/2) * K * x^2

Where,

K is the force constant of the spring

x is the displacement of the spring


Let the displacement of both the springs be x.

The force acting on spring 1 is F = K1 * x

The force acting on spring 2 is F = K2 * x


The displacement of each spring is equal, so the elastic potential energy of each spring is,

E1 = (1/2) * K1 * x^2

E2 = (1/2) * K2 * x^2


Dividing E1 by E2,

E1/E2 = [(1/2) * K1 * x^2] / [(1/2) * K2 * x^2]

E1/E2 = K1/K2


Therefore, the ratio of elastic potential energies of the two springs is K1/K2.


Answer:

The ratio of elastic potential energies of the two springs is A) K1/K2.
Community Answer
Two springs have force constant K1 and K2, (K1>K2). Each spring is ext...
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Two springs have force constant K1 and K2, (K1>K2). Each spring is extended by same force F. If their elastic potential energy is E1 and E2, then E1/E2 is A) K1/K2 B) K2/K2 C) √(K1/K2) D) √(K2/K1)?
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Two springs have force constant K1 and K2, (K1>K2). Each spring is extended by same force F. If their elastic potential energy is E1 and E2, then E1/E2 is A) K1/K2 B) K2/K2 C) √(K1/K2) D) √(K2/K1)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two springs have force constant K1 and K2, (K1>K2). Each spring is extended by same force F. If their elastic potential energy is E1 and E2, then E1/E2 is A) K1/K2 B) K2/K2 C) √(K1/K2) D) √(K2/K1)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two springs have force constant K1 and K2, (K1>K2). Each spring is extended by same force F. If their elastic potential energy is E1 and E2, then E1/E2 is A) K1/K2 B) K2/K2 C) √(K1/K2) D) √(K2/K1)?.
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