NEET Exam > NEET Questions > A spring with potential constant k when compr...
Start Learning for Free
A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ?
Most Upvoted Answer
A spring with potential constant k when compressed by 1cm the p.e stor...
Compression of a Spring and Change in Potential Energy
Introduction:
When a spring is compressed or stretched, it stores potential energy due to its elastic properties. The amount of potential energy stored in a compressed spring can be determined by the potential constant of the spring, denoted as k.
Given:
- The potential constant of the spring, k.
- The spring is initially compressed by 1 cm.
Calculating Potential Energy:
The potential energy stored in a spring can be calculated using the formula:
U = (1/2) * k * x^2
Where:
U is the potential energy stored in the spring,
k is the potential constant of the spring, and
x is the displacement or compression of the spring.
Step 1: Calculating Potential Energy for 1 cm Compression:
Given that the spring is initially compressed by 1 cm, we can substitute this value into the formula to calculate the potential energy stored in the spring:
U1 = (1/2) * k * (0.01)^2
U1 = (1/2) * k * 0.0001
U1 = 0.00005 * k
Calculating Change in Potential Energy:
To find the change in potential energy when the spring is further compressed by 3 cm, we need to calculate the potential energy for this new compression and then find the difference between the two potential energy values.
Step 2: Calculating Potential Energy for 4 cm Compression:
Now, let's consider the spring being further compressed by 3 cm. The total compression becomes 1 cm + 3 cm = 4 cm.
Using the formula, we can calculate the potential energy stored in the spring for this new compression:
U2 = (1/2) * k * (0.04)^2
U2 = (1/2) * k * 0.0016
U2 = 0.0008 * k
Step 3: Calculating Change in Potential Energy:
To find the change in potential energy, we subtract the initial potential energy from the final potential energy:
Change in Potential Energy = U2 - U1
Change in Potential Energy = 0.0008 * k - 0.00005 * k
Change in Potential Energy = (0.0008 - 0.00005) * k
Change in Potential Energy = 0.00075 * k
Conclusion:
The change in potential energy when the spring is further compressed by 3 cm is 0.00075 times the potential constant of the spring (k).
Introduction:
When a spring is compressed or stretched, it stores potential energy due to its elastic properties. The amount of potential energy stored in a compressed spring can be determined by the potential constant of the spring, denoted as k.
Given:
- The potential constant of the spring, k.
- The spring is initially compressed by 1 cm.
Calculating Potential Energy:
The potential energy stored in a spring can be calculated using the formula:
U = (1/2) * k * x^2
Where:
U is the potential energy stored in the spring,
k is the potential constant of the spring, and
x is the displacement or compression of the spring.
Step 1: Calculating Potential Energy for 1 cm Compression:
Given that the spring is initially compressed by 1 cm, we can substitute this value into the formula to calculate the potential energy stored in the spring:
U1 = (1/2) * k * (0.01)^2
U1 = (1/2) * k * 0.0001
U1 = 0.00005 * k
Calculating Change in Potential Energy:
To find the change in potential energy when the spring is further compressed by 3 cm, we need to calculate the potential energy for this new compression and then find the difference between the two potential energy values.
Step 2: Calculating Potential Energy for 4 cm Compression:
Now, let's consider the spring being further compressed by 3 cm. The total compression becomes 1 cm + 3 cm = 4 cm.
Using the formula, we can calculate the potential energy stored in the spring for this new compression:
U2 = (1/2) * k * (0.04)^2
U2 = (1/2) * k * 0.0016
U2 = 0.0008 * k
Step 3: Calculating Change in Potential Energy:
To find the change in potential energy, we subtract the initial potential energy from the final potential energy:
Change in Potential Energy = U2 - U1
Change in Potential Energy = 0.0008 * k - 0.00005 * k
Change in Potential Energy = (0.0008 - 0.00005) * k
Change in Potential Energy = 0.00075 * k
Conclusion:
The change in potential energy when the spring is further compressed by 3 cm is 0.00075 times the potential constant of the spring (k).
Community Answer
A spring with potential constant k when compressed by 1cm the p.e stor...
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ?
Question Description
A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ?.
A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ?.
Solutions for A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ? defined & explained in the simplest way possible. Besides giving the explanation of
A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ?, a detailed solution for A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ? has been provided alongside types of A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ? theory, EduRev gives you an
ample number of questions to practice A spring with potential constant k when compressed by 1cm the p.e stored by U . if it is further compressed by 3cm ,then change in potential energy is ? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup