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Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y?
Verified Answer
Two solids X and Y dissociates into Gaseous products at a certain temp...
We know, Kp = (Pa*Pc)/Px for the first one. As x is a solid so Px = 1
Total pressure = 40 mm = pressure of A and pressure of C = x+x=2x Let pressure of one molecule at equilibrium = x
So 2x = 40 mm = 0.052 atm (as 1 atm 760 mm)
x = 0.026 atm
So Kp = 0.026*0.026 = 0.000676
Similarly for the second reaction
x = 80/2 = 40 mm = 0.052 atm
So Kp = 0.052*0.052 = 0.00270
The ratio of moles of A:B = 1:1
Total pressure over X and Y = 48+80=120 mm
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Most Upvoted Answer
Two solids X and Y dissociates into Gaseous products at a certain temp...
Pressure of A and B in the vapor state over a mixture of X and Y:
Given data:
- Solid X dissociates into gases A and C.
- Solid Y dissociates into gases B and C.
- Pressure over excess solid X is 40 mm.
- Pressure over excess solid Y is 60 mm.
Step 1: Understanding the dissociation reactions:
- X(s) dissociates into A(g) and C(g).
- Y(s) dissociates into B(g) and C(g).
Step 2: Determining the partial pressure of A and B:
- The total pressure over a mixture of X and Y is the sum of the partial pressures of A, B, and C.
- As both X and Y dissociate into C, the partial pressure of C is the sum of the pressures over excess solid X and Y: 40 mm + 60 mm = 100 mm.
- Since the total pressure is 100 mm, the partial pressure of A and B must be less than 100 mm.
Step 3: Applying Dalton's Law of Partial Pressures:
- Dalton's Law states that the total pressure exerted by a mixture of non-reacting gases is equal to the sum of the partial pressures of each individual gas.
- Therefore, the pressure of A and B in the vapor state over a mixture of X and Y is less than 100 mm, but their exact values cannot be determined without additional information.
Conclusion:
- The pressure of A and B in the vapor state over a mixture of X and Y cannot be determined solely based on the given information.
- The partial pressures of A and B depend on the extent of dissociation of solids X and Y, which requires additional data such as equilibrium constants or reaction rates.
- To calculate the exact pressures of A and B, more information about the dissociation reactions or the equilibrium conditions is needed.
Given data:
- Solid X dissociates into gases A and C.
- Solid Y dissociates into gases B and C.
- Pressure over excess solid X is 40 mm.
- Pressure over excess solid Y is 60 mm.
Step 1: Understanding the dissociation reactions:
- X(s) dissociates into A(g) and C(g).
- Y(s) dissociates into B(g) and C(g).
Step 2: Determining the partial pressure of A and B:
- The total pressure over a mixture of X and Y is the sum of the partial pressures of A, B, and C.
- As both X and Y dissociate into C, the partial pressure of C is the sum of the pressures over excess solid X and Y: 40 mm + 60 mm = 100 mm.
- Since the total pressure is 100 mm, the partial pressure of A and B must be less than 100 mm.
Step 3: Applying Dalton's Law of Partial Pressures:
- Dalton's Law states that the total pressure exerted by a mixture of non-reacting gases is equal to the sum of the partial pressures of each individual gas.
- Therefore, the pressure of A and B in the vapor state over a mixture of X and Y is less than 100 mm, but their exact values cannot be determined without additional information.
Conclusion:
- The pressure of A and B in the vapor state over a mixture of X and Y cannot be determined solely based on the given information.
- The partial pressures of A and B depend on the extent of dissociation of solids X and Y, which requires additional data such as equilibrium constants or reaction rates.
- To calculate the exact pressures of A and B, more information about the dissociation reactions or the equilibrium conditions is needed.
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Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y?
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Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y?.
Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y?.
Solutions for Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y? in English & in Hindi are available as part of our courses for NEET.
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Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y?, a detailed solution for Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y? has been provided alongside types of Two solids X and Y dissociates into Gaseous products at a certain temperature as follows X(s) ---- A(g) C(g) and Y(s) ---- B(g) C(g). At a given temperature, pressure over excess solid X is 40mm and total pressure over excess solid Y is 60mm. In a mixture of X and Y, calculate the pressure of A and B in the vapour state over a mixture of X and Y? theory, EduRev gives you an
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