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Depression in freezing point is 6K for Nacl solution .Of for water is 1.86K/kg mole ,amount of NaCl dissolved in 1kg of water is?
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Calculation of Amount of NaCl Dissolved in 1kg of Water:
1. Given:
- Depression in freezing point = 6K
- Depression in freezing point for water = 1.86K/kg mole
2. Formula:
- \[ \Delta Tf = K_f \times m \]
- Where \(\Delta Tf\) = Depression in freezing point, \(K_f\) = Freezing point depression constant, and \(m\) = Molality of the solution
3. Calculating Molality:
- Molality (\(m\)) can be calculated using the formula:
\[ m = \frac{\Delta Tf}{K_f} \]
4. Substitute the Values:
- Given \(\Delta Tf = 6K\) and \(K_f = 1.86K/kg mole\), we can find the molality of the solution:
\[ m = \frac{6}{1.86} = 3.23 mol/kg \]
5. Calculating Amount of NaCl Dissolved:
- The molality of the solution is 3.23 mol/kg, which means there are 3.23 moles of NaCl dissolved in 1 kg of water.
6. Converting Moles to Mass:
- The molar mass of NaCl is 58.44 g/mol. Therefore, the mass of NaCl dissolved in 1 kg of water would be:
\[ Mass = 3.23 mol \times 58.44 g/mol = 188.53 g \]
7. Conclusion:
- The amount of NaCl dissolved in 1 kg of water is 188.53 grams.
1. Given:
- Depression in freezing point = 6K
- Depression in freezing point for water = 1.86K/kg mole
2. Formula:
- \[ \Delta Tf = K_f \times m \]
- Where \(\Delta Tf\) = Depression in freezing point, \(K_f\) = Freezing point depression constant, and \(m\) = Molality of the solution
3. Calculating Molality:
- Molality (\(m\)) can be calculated using the formula:
\[ m = \frac{\Delta Tf}{K_f} \]
4. Substitute the Values:
- Given \(\Delta Tf = 6K\) and \(K_f = 1.86K/kg mole\), we can find the molality of the solution:
\[ m = \frac{6}{1.86} = 3.23 mol/kg \]
5. Calculating Amount of NaCl Dissolved:
- The molality of the solution is 3.23 mol/kg, which means there are 3.23 moles of NaCl dissolved in 1 kg of water.
6. Converting Moles to Mass:
- The molar mass of NaCl is 58.44 g/mol. Therefore, the mass of NaCl dissolved in 1 kg of water would be:
\[ Mass = 3.23 mol \times 58.44 g/mol = 188.53 g \]
7. Conclusion:
- The amount of NaCl dissolved in 1 kg of water is 188.53 grams.
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Depression in freezing point is 6K for Nacl solution .Of for water is 1.86K/kg mole ,amount of NaCl dissolved in 1kg of water is?
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Depression in freezing point is 6K for Nacl solution .Of for water is 1.86K/kg mole ,amount of NaCl dissolved in 1kg of water is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Depression in freezing point is 6K for Nacl solution .Of for water is 1.86K/kg mole ,amount of NaCl dissolved in 1kg of water is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Depression in freezing point is 6K for Nacl solution .Of for water is 1.86K/kg mole ,amount of NaCl dissolved in 1kg of water is?.
Depression in freezing point is 6K for Nacl solution .Of for water is 1.86K/kg mole ,amount of NaCl dissolved in 1kg of water is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Depression in freezing point is 6K for Nacl solution .Of for water is 1.86K/kg mole ,amount of NaCl dissolved in 1kg of water is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Depression in freezing point is 6K for Nacl solution .Of for water is 1.86K/kg mole ,amount of NaCl dissolved in 1kg of water is?.
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