NEET Exam > NEET Questions > A mixture of ethyl alcohol and propyl alcohol...
Start Learning for Free
A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?
Most Upvoted Answer
A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of...
Community Answer
A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of...
Calculating Vapour Pressure of Ethyl Alcohol
Given:
Mole fraction of ethyl alcohol (Xethanol) = 0.6
Vapour pressure of the mixture (Pmixture) = 290 mm
Vapour pressure of propyl alcohol (Ppropyl) = 200 mm
To find: Vapour pressure of ethyl alcohol (Pethanol)
Formula used:
Dalton's Law of Partial Pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases in the mixture.
Thus, Pmixture = Pethanol + Ppropyl
Also, mole fraction of a component is given by:
Xethanol = nethanol / (nethanol + npropyl)
where nethanol and npropyl are the number of moles of ethanol and propyl alcohol present in the mixture respectively.
Solution:
Let's first calculate the mole fraction of propyl alcohol:
Xpropyl = 1 - Xethanol = 1 - 0.6 = 0.4
Now, using the mole fraction, we can write:
nethanol = Xethanol * ntotal
npropyl = Xpropyl * ntotal
where ntotal is the total number of moles of both alcohols present in the mixture.
We can rearrange these equations to get:
ntotal = nethanol / Xethanol = npropyl / Xpropyl
Substituting the values, we get:
ntotal = nethanol / 0.6 = npropyl / 0.4
or, nethanol = 0.6 * ntotal and npropyl = 0.4 * ntotal
Now, using Dalton's Law of Partial Pressures, we have:
Pmixture = Pethanol + Ppropyl
or, 290 mm = Pethanol + 200 mm
or, Pethanol = 90 mm
Therefore, the
Given:
Mole fraction of ethyl alcohol (Xethanol) = 0.6
Vapour pressure of the mixture (Pmixture) = 290 mm
Vapour pressure of propyl alcohol (Ppropyl) = 200 mm
To find: Vapour pressure of ethyl alcohol (Pethanol)
Formula used:
Dalton's Law of Partial Pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases in the mixture.
Thus, Pmixture = Pethanol + Ppropyl
Also, mole fraction of a component is given by:
Xethanol = nethanol / (nethanol + npropyl)
where nethanol and npropyl are the number of moles of ethanol and propyl alcohol present in the mixture respectively.
Solution:
Let's first calculate the mole fraction of propyl alcohol:
Xpropyl = 1 - Xethanol = 1 - 0.6 = 0.4
Now, using the mole fraction, we can write:
nethanol = Xethanol * ntotal
npropyl = Xpropyl * ntotal
where ntotal is the total number of moles of both alcohols present in the mixture.
We can rearrange these equations to get:
ntotal = nethanol / Xethanol = npropyl / Xpropyl
Substituting the values, we get:
ntotal = nethanol / 0.6 = npropyl / 0.4
or, nethanol = 0.6 * ntotal and npropyl = 0.4 * ntotal
Now, using Dalton's Law of Partial Pressures, we have:
Pmixture = Pethanol + Ppropyl
or, 290 mm = Pethanol + 200 mm
or, Pethanol = 90 mm
Therefore, the
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Top Courses for NEETView all
A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?
Question Description
A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?.
A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?.
Solutions for A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? defined & explained in the simplest way possible. Besides giving the explanation of
A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?, a detailed solution for A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? has been provided alongside types of A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? theory, EduRev gives you an
ample number of questions to practice A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup