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A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?
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Calculating Vapour Pressure of Ethyl Alcohol
Given:
Mole fraction of ethyl alcohol (Xethanol) = 0.6
Vapour pressure of the mixture (Pmixture) = 290 mm
Vapour pressure of propyl alcohol (Ppropyl) = 200 mm
To find: Vapour pressure of ethyl alcohol (Pethanol)
Formula used:
Dalton's Law of Partial Pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases in the mixture.
Thus, Pmixture = Pethanol + Ppropyl
Also, mole fraction of a component is given by:
Xethanol = nethanol / (nethanol + npropyl)
where nethanol and npropyl are the number of moles of ethanol and propyl alcohol present in the mixture respectively.
Solution:
Let's first calculate the mole fraction of propyl alcohol:
Xpropyl = 1 - Xethanol = 1 - 0.6 = 0.4
Now, using the mole fraction, we can write:
nethanol = Xethanol * ntotal
npropyl = Xpropyl * ntotal
where ntotal is the total number of moles of both alcohols present in the mixture.
We can rearrange these equations to get:
ntotal = nethanol / Xethanol = npropyl / Xpropyl
Substituting the values, we get:
ntotal = nethanol / 0.6 = npropyl / 0.4
or, nethanol = 0.6 * ntotal and npropyl = 0.4 * ntotal
Now, using Dalton's Law of Partial Pressures, we have:
Pmixture = Pethanol + Ppropyl
or, 290 mm = Pethanol + 200 mm
or, Pethanol = 90 mm
Therefore, the
Given:
Mole fraction of ethyl alcohol (Xethanol) = 0.6
Vapour pressure of the mixture (Pmixture) = 290 mm
Vapour pressure of propyl alcohol (Ppropyl) = 200 mm
To find: Vapour pressure of ethyl alcohol (Pethanol)
Formula used:
Dalton's Law of Partial Pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases in the mixture.
Thus, Pmixture = Pethanol + Ppropyl
Also, mole fraction of a component is given by:
Xethanol = nethanol / (nethanol + npropyl)
where nethanol and npropyl are the number of moles of ethanol and propyl alcohol present in the mixture respectively.
Solution:
Let's first calculate the mole fraction of propyl alcohol:
Xpropyl = 1 - Xethanol = 1 - 0.6 = 0.4
Now, using the mole fraction, we can write:
nethanol = Xethanol * ntotal
npropyl = Xpropyl * ntotal
where ntotal is the total number of moles of both alcohols present in the mixture.
We can rearrange these equations to get:
ntotal = nethanol / Xethanol = npropyl / Xpropyl
Substituting the values, we get:
ntotal = nethanol / 0.6 = npropyl / 0.4
or, nethanol = 0.6 * ntotal and npropyl = 0.4 * ntotal
Now, using Dalton's Law of Partial Pressures, we have:
Pmixture = Pethanol + Ppropyl
or, 290 mm = Pethanol + 200 mm
or, Pethanol = 90 mm
Therefore, the
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A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?
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A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?.
A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?.
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A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350?, a detailed solution for A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? has been provided alongside types of A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300k. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, it's vapour pressure (in mm) at the same temperature will be A) 300 B) 700 C) 360 D) 350? theory, EduRev gives you an
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