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All questions of Organic Chemistry for ACT Exam

Which among the following is not an aromatic compound(in specific)
  • a)
    Naphthalene
  • b)
    Aniline
  • c)
    Pyridine
  • d)
    Tropolone
Correct answer is option 'C'. Can you explain this answer?

Sai Mishra answered
Pyridine is heterocyclic aromatic compound. Whereas naphthalene and aniline are benzenoid aromatic compounds and tropolone is a non-benzenoid aromatic compound.

Which of the following is the correct IUPAC name?
  • a)
    5-Ethyl-4, 4-dimethylheptane
  • b)
    4, 4-Dimethyl-3-ethylheptane
  • c)
    3-Ethyl-4, 4-dimethylheptane
  • d)
    4, 4-Bis(methyl)-3-ethylheptane
Correct answer is option 'C'. Can you explain this answer?

Raghav Bansal answered
 While writing IUPAC name, the alkyl groups are written in alphabetical order. Thus lower locant 3 is assigned to ethyl. Prefix, di, tri, and tetra are not included in alphabetical order.

Organic compounds are broadly classified as
  • a)
    alicyclic compounds and acyclic compounds
  • b)
    Open chain compounds and linear chain compounds
  • c)
    Cyclic compounds and alicyclic compounds
  • d)
    Open chain compounds and closed compounds
Correct answer is option 'D'. Can you explain this answer?

Arpita Nambiar answered
The correct answer is option D
Organic compounds are broadly classified into open chain and closed chain compounds. Explanation: open chain compounds or acyclic compounds are otherwise called as aliphatic compounds.

Nitration of benzene is:
  • a)
    Free radical substitution reaction
  • b)
    Nucleophilic addition reaction
  • c)
    Nucleophilic substitution reaction
  • d)
    Electrophilic substitution reaction
Correct answer is option 'D'. Can you explain this answer?

Arun Khanna answered
Nitration and sulfonation of benzene are two examples of electrophilic aromatic substitution. The nitronium ion (NO2+) and sulfur trioxide (SO3) are the electrophiles and individually react with benzene to give nitrobenzene and benzenesulfonic acid respectively.

This apparatus provides many surfaces for heat exchange between the ascending vapours and the descending condensed liquid.
  • a)
    Round bottom flask
  • b)
    Pipette
  • c)
    Burette
  • d)
    Fractionating column
Correct answer is option 'D'. Can you explain this answer?

Anand Kapoor answered
**Explanation:**

The correct answer is option D, the fractionating column. Let's break down the explanation:

**1. Heat Exchange:**
The apparatus mentioned in the question is designed to facilitate heat exchange between ascending vapors and descending condensed liquid. Heat exchange is an essential process that occurs in various applications, such as distillation, where it helps in separating mixtures based on differences in boiling points.

**2. Surfaces for Heat Exchange:**
The apparatus should provide multiple surfaces or stages where heat exchange can occur. This means that the ascending vapors and descending condensed liquid should come into close contact with each other, allowing thermal energy transfer.

**3. Round Bottom Flask, Pipette, and Burette:**
The options A (round bottom flask), B (pipette), and C (burette) do not meet the criteria for providing multiple surfaces for heat exchange. Let's briefly explain why:

- **Round Bottom Flask (Option A):** A round bottom flask is a commonly used laboratory glassware that is primarily used for holding liquids and conducting chemical reactions. It does not provide multiple surfaces for heat exchange as required in the question.

- **Pipette (Option B):** A pipette is a laboratory tool used for accurately measuring and transferring small volumes of liquids. It is not designed for heat exchange between ascending vapors and descending condensed liquid.

- **Burette (Option C):** A burette is a long, graduated glass tube with a stopcock at the bottom. It is commonly used in titrations for precise volume measurements but does not provide the required surfaces for heat exchange.

**4. Fractionating Column (Option D):**
The fractionating column is a specially designed apparatus used in distillation processes to achieve separation of liquid mixtures based on differences in boiling points. It consists of multiple stages or trays, providing numerous surfaces for heat exchange.

- **Heat Exchange in the Fractionating Column:** As the vapor rises through the fractionating column, it comes into contact with the descending condensed liquid. Heat is exchanged between the ascending vapors and the descending liquid, allowing the separation of components with different boiling points.

- **Multiple Surfaces for Heat Exchange:** The fractionating column contains several trays or stages, each acting as a surface for heat exchange. The vapors and condensed liquid interact on these trays, promoting efficient heat transfer between the two phases.

Therefore, the fractionating column is the apparatus that best fits the description provided in the question, offering multiple surfaces for heat exchange between ascending vapors and descending condensed liquid.

C1 - C2 bond of this molecules is formed by:
  • a)
    sp3-sp2 overlap
  • b)
    sp2-sp3 overlap
  • c)
    sp2-sp overlap
  • d)
    sp2-sp2 overlap
Correct answer is option 'C'. Can you explain this answer?

Snehal answered
I draw Actual structure For U=> CH2 = CH-C=_ N u can see between C & N there are three bonds (1 sigma & 2 π bonds) NOTE FOR U ==> (1) if carbon is singly bonded only then sp^3 hybridisation (2) if there is one π bond only then sp^2 hybridisation (3) if there is 2 π bonds then there is sp hybridisation ________ So now u use this given information and conclude answer by ur own self 😄😄😄😃

Among these canonical structures, the correct order of stability is
  • a)
    I > II > III
  • b)
    III > II > I
  • c)
    I > III > II
  • d)
    II > I > III
Correct answer is option 'C'. Can you explain this answer?

Armaan Sharma answered
In structure no 1 no charge is present.in third one positive charge is on "OH" which sjows negative I effect and also "O" atom is more electronegative than C so 3rd is more stable than 2

Process of separation of mixtures into their components and to purify the compounds by using adsorption is known as:
  • a)
    Sublimation
  • b)
    Differential extraction
  • c)
    Distillation
  • d)
    Chromatography
Correct answer is option 'D'. Can you explain this answer?

Hansa Sharma answered
The correct answer is Option D.
Chromatography is an important separation technique used to separate constituent particles of a mixture of substances, to purify the compounds and check the purity of organic compounds. In this technique on a stationary phase (solid or a liquid) a mixture of substances is applied. The mixture of gas or the pure solvent is allowed to move slowly on the stationary phase. Due to which the components of the mixture start separating from one another.

 Rate of reaction of alkanes with halogens is:
  • a)
    Br2> I2>F2>Cl2
  • b)
    Cl2> Br2> I2>F2
  • c)
    F2>Cl2> Br2> I2
  • d)
    Cl2> Br2>F2> I2
Correct answer is option 'C'. Can you explain this answer?

Krishna Iyer answered
The correct answer is option C
The reactivity of the halogens decreases in the following order: F2​>Cl2​>Br2​>I2
fluorine is so explosively reactive it is difficult to control, and iodine is generally unreactive. Chlorination and bromination are normally exothermic.

 Identify the odd one among the following
  • a)
    Indene
  • b)
    Anthracene
  • c)
    o,m,p-xylene
  • d)
    Azulene
Correct answer is option 'D'. Can you explain this answer?

Saumya Ahuja answered
Azulene is a non- benzenoid compound. Whereas, Indene, anthracene, and o,m,p-Xylene are examples of benzenoid aromatic compounds.

Which one of the following is the strongest acid ?
  • a)
    Cl3CCOOH
  • b)
    ClCH2 COOH
  • c)
    Cl2CH COOH
  • d)
    CH3 COOH
Correct answer is option 'A'. Can you explain this answer?

Strongest Acid: Cl3CCOOH

Explanation:

1. Introduction

In order to determine the strongest acid among the given options, we need to analyze their molecular structures and the strength of the bonds within them.

2. Molecular Structures

Let's examine the molecular structures of the given acids:

a) Cl3CCOOH (Trichloroacetic acid)
b) ClCH2COOH (Chloroacetic acid)
c) Cl2CHCOOH (Dichloroacetic acid)
d) CH3COOH (Acetic acid)

3. Analysis of Acidity

The strength of an acid is determined by its ability to donate a proton (H+). Acids with more stable conjugate bases are stronger, as they are more likely to donate a proton.

a) Trichloroacetic acid (Cl3CCOOH) has three chlorine atoms bonded to the central carbon atom. The electronegativity of chlorine is higher than that of carbon, causing the Cl-C bond to be polarized. This polarization weakens the carbon-hydrogen bond, making it easier for the acid to donate a proton. Therefore, Cl3CCOOH is the strongest acid among the given options.

b) Chloroacetic acid (ClCH2COOH) has one chlorine atom bonded to the central carbon atom. The presence of chlorine weakens the carbon-hydrogen bond, but not as much as in trichloroacetic acid.

c) Dichloroacetic acid (Cl2CHCOOH) has two chlorine atoms bonded to the central carbon atom. The presence of two chlorine atoms further weakens the carbon-hydrogen bond compared to chloroacetic acid.

d) Acetic acid (CH3COOH) does not have any chlorine atoms bonded to the central carbon atom. Therefore, the carbon-hydrogen bond is stronger compared to the other three acids.

4. Conclusion

Among the given options, trichloroacetic acid (Cl3CCOOH) is the strongest acid. This is due to the presence of three chlorine atoms, which weaken the carbon-hydrogen bond and make it easier for the acid to donate a proton.

 Addition of dihydrogen to propyne forms:
  • a)
    Ethanal
  • b)
    Carbocation
  • c)
    Propene
  • d)
    carbanion
Correct answer is option 'C'. Can you explain this answer?

Rahul Bansal answered
Propene, also known as propylene or methyl ethylene, is an unsaturated organic compound having the chemical formula . It has one double bond, and is the second simplest member of the alkene class of hydrocarbons.

What is relationship between the following Fischer Projections?
  • a)
    Enantiomers
  • b)
    Diastereomersb
  • c)
    Conformers
  • d)
    Structural Isomers
Correct answer is option 'C'. Can you explain this answer?

Suresh Reddy answered
The correct answer is option C
Conformers are isomers having the same bond connectivity sequence and can be interconverted by rotation around one or more single (σ) bonds. Hence, the two structures represent conformers.

In which of the following, functional group isomerism is not possible?
  • a)
    Alcohols
  • b)
    Aldehydes
  • c)
    Alkyl halides
  • d)
    Cyanides
Correct answer is option 'C'. Can you explain this answer?

Naina Menon answered
Alkyl halides do not show functional isomerism. Alcohols and ethers, aldehydes and ketones, cyanides and isocyanides are functional isomers.

Which of the following correctly ranks the cycloalkanes in order of increasing ring strain per methylene group? 
  • a)
    Cyclopropane < Cyclobutane < Cyclopentane < Cyclohexane 
  • b)
    Cyclohexane < Cyclopentane < Cyclobutane < Cyclopropane 
  • c)
    Cyclohexane < Cyclobutane < Cyclopentane < Cyclopropane 
  • d)
    Cyclopropane < Cyclopentane < Cyclobutane < Cyclohexane  
Correct answer is option 'B'. Can you explain this answer?

Rajesh Gupta answered
The correct answer is Option B.

The C-C-C bond angles in cyclopropane (60o) and cyclobutane (90o) are much different than the ideal bond angle of 109.5o.This bond angle causes cyclopropane and cyclobutane to have a high ring strain. However, molecules, such as cyclohexane and cyclopentane, would have a much lower ring strain because the bond angle between the carbons is much closer to 109.5o.

Bond formation is:
  • a)
    always exothermic
  • b)
    always endothermic
  • c)
    neither exothermic nor endothermic
  • d)
    sometimes exothermic and sometimes endothermic
Correct answer is option 'A'. Can you explain this answer?

Ankit Mode answered
Bond is formed if atoms are getting more stable after bond formation and being stable means less energy state so they release energy while bond formation so it is exothermic process

 In Friedel crafts alkylation and acylation the attacking reagent is an:
  • a)
    Electrophile
  • b)
    Nucleophile
  • c)
    Radical
  • d)
    Ionic species
Correct answer is option 'A'. Can you explain this answer?

A Friedel-Crafts alkylation reaction is an electrophilic aromatic substitution reaction in which a carbocation attacks an aromatic ring with the net result that one of the aromatic protons is replaced by an alkyl group. vinyl and aryl halides cannot be used to form carbocations.

 Distance moved by the substance from the base line to the distance moved by the solvent from the base line is known as the:
  • a)
    Df value
  • b)
    Hf value
  • c)
    Rf value
  • d)
    Tf value
Correct answer is option 'C'. Can you explain this answer?

Ayush Joshi answered
The Rf value is defined as the ratio of the distance moved by the solute and the distance moved by the the solvent along the paper, where both distances are measured from the common Origin or Application Baseline, that is the point where the sample is initially spotted on the paper.

Find the odd one among the following:
  • a)
    Alicyclic compounds
  • b)
    Heterogeneous compounds
  • c)
    Branched chain compounds
  • d)
    Aromatic compounds
Correct answer is option 'C'. Can you explain this answer?

Shruti Ahuja answered
Branched chain compound is a classification of open-chain compounds. Whereas, alicyclic, aromatic and heterogeneous compounds are sub-classifications of cyclic compounds.

In which of the following pairs, first species is more stable than second ?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'D'. Can you explain this answer?

Sakshi Jain answered
Due to delocalisation of charge at 3 consecutive places and hence more no.of resonating structures.So 'd' is correct option.

In which of the following molecels both phenyl rings are not coplanar ?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'D'. Can you explain this answer?

Mahanda answered
Option D is non planar due to steric hindrance at the ortho position.All the other three are co planar.

Which among the following is not a class of organic compound
  • a)
    Carbonyl compound
  • b)
    Nitro compound
  • c)
    Amides
  • d)
    Electro compounds
Correct answer is option 'D'. Can you explain this answer?

Ishani Mehta answered
Classes of organic compounds are those which involves organic compounds such as carbon, hydrogen and oxygen. Hence, electro compounds is not a class of organic compounds.

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