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All questions of Coordination Compounds for NEET Exam

If zeise’s salt has the formula [Pt(C2H4)CI3]-. In this, platinum primary and secondary valency are
  • a)
    + 1 and 3
  • b)
    + 1 and 4
  • c)
    + 3 and 4
  • d)
    + 4 and 6
Correct answer is option 'B'. Can you explain this answer?

Krishna Iyer answered
Let the oxidation state of pt be x.
Oxidation state of cl is -1.
So x + 0 – (1*3) must be equal to -1 since the charge of the whole compound is -1.
x + 0 – (1*3) = -1
x -3 = -1
x = -1 + 3
x = +2
So the oxidation state of platinum is +2.
Secondary is due to legend there are mono deadened legend 
then 1×4= 4
 
Clear all your doubts with EduRev

Type of bonding in K4 [Fe(CN)6] is/a
  • a)
    ionic
  • b)
    covalent
  • c)
    metallic
  • d)
    coordinate covalent
Correct answer is option 'A,B,D'. Can you explain this answer?

Shubham Jain answered
The complex K4[Fe(CN)6] whose formula can be written like that of double salt. Fe(CN)2 . 4KCN, dissociates to give K+ and [Fe(CN)6]4- ions in the aqueous solution.

Earth's atmosphere is richest in :
  • a)
    ultraviolet
  • b)
    infrared
  • c)
    X-rays
  • d)
    microwaves
Correct answer is option 'B'. Can you explain this answer?

Geetika Shah answered
The correct answer is Option B. 
Earth 's atmosphere is richest in infrared radiation or IR.
* The earth emits huge amounts of infrared radiation and thereby makes the atmosphere richest in infrared rays.
* When sunlight (solar radiation) hits the earth, some of the energy is absorbed by the earth that ultimately heats up the earth.
* This heat gets radiated by the earth in the form of infrared radiation.
 

The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6 is
  • a)
    0
  • b)
    2.84
  • c)
    4.90
  • d)
    5.92
Correct answer is option 'A'. Can you explain this answer?

Rahul Bansal answered
The electron configuration is [Ar]3d^5 4s^1.We have to accomodate the 6 Ligands and the fact that CO is a strong ligand.
This results in d^2sp^3 hybridization. Therefore, there are no unpaired electrons in Cr(CO)6. Hence n=0
And the spin only magnetic moment is also 0.

The effective atomic number of Fe in Fe(CO)5 is
  • a)
    36
  • b)
    24
  • c)
    34
  • d)
    26
Correct answer is option 'A'. Can you explain this answer?

Anupama Nair answered
EAN= atomic no of Fe - oxidation state + no of e donated by ligand... Oxidation state of Fe is 0 since CO is neutral ligand... Two donor atoms hence no of e = 2×5=10.... EAN= 26-0+10=36

Which of the following statements is/are correct?
  • a)
    [Co(en)2NO2Cl] Br is cationic complex
  • b)
    [Co(en)3]CI3 produces 3 ions in solution
  • c)
    [Fe(CO)5] is neutral complex
  • d)
    [Cu(NH3)4]SO4 is deep blue colour
Correct answer is option 'A,C,D'. Can you explain this answer?

Nikita Singh answered
[Co(en)3]CI3 produces 4 ions in solution as follows :
[Co(en)3] CI3→ [Co(en)3]3+ + 3CI-
 
  1. is correct as charge on the complex ion will be +1
  2.  is incorrect as the complex will form 4 ions in solution
  3. is correct as there is no charge on the complex
  4. is also correct as cu+2 has blue color in solution
Hence A, C and D are correct.

Which of the following complex ion is not expected to absorb visible light ? [2010]
  • a)
    Ni(CN)42
  • b)
    Cr(NH3)6 3
  • c)
    2Fe(H2 O)6
  • d)
    Ni(H2O)62
Correct answer is option 'A'. Can you explain this answer?

Mahesh Saini answered
Absorption of visual light is associated with an energy difference between two orbitals — one occupied, one unoccupied — and electrons must be able to be excited from one to the other.

In coordination complexes, these excitations typically happen within the metal’s d subshell, so it is usually sufficient to examine that and approximately determine which excitations are possible. The main selection rules are:

the spin rule. The electron must be excitable without a spin-flip
the Laporte rule. Basically, d to d transitions are forbidden in octahedral complexes
The spin rule is very strongly observed. The color of manganese(II) whose transition is spin-forbidden is extremely faint. The Laporte rule only holds true as long as the complex is inversion-symmetric, so any asymmetric vibration is enough to make it void; thus, Laporte-forbidden transitions are typically still visible but somewhat faint.

Let’s examine the complexes:

[Ni(CN)4]2−This is expected to be square planar and d8. The energy difference between the two highest orbitals — dxy and dx2−y2 — is expected to be high. The former is expected to be fully populated, the latter to be unpopulated.
[Cr(NH3)6]3+ This is a d3 system. It is expected to be octahedral with a standard difference between the lower and higher energy levels.
[Fe(H2O)6]2+This is a d6 octahedral system. There is no reason to assume a low spin state. The energy difference is expected to be slightly less than in the previous case.
[Ni(H2O)6]2+ this is expected to be a high-spin d8system and octahedral. The same expectation regarding energy levels as on the previous case applies.
We realize that the of our complexes are average high spin octahedral complexes. For these, visible light absorption is always expected. Only one case is different. In that different case, the HOMO-LUMO difference is large. While we can still expect absorption, it seems most reasonable to assign this absorption band an ultraviolet wavelength.

Thus, [Ni(CN)4]2− is the answer.

The complex potassium dicyanodioxalatonickelate (II) in solution produce....... ions.
    Correct answer is '5'. Can you explain this answer?

    Anaya Patel answered
    The structure of potassium dicyanodio xalatonickelate (II) is
    K4[Ni(CN)2(ox)2].
    K4[Ni(CN)2(ox)2] →  4K+ + [Ni(CN)2(ox)2]- 
    This produce 5 ions in solution.

    Number of EDTA molecules required to form an octahedral complex.
      Correct answer is '1'. Can you explain this answer?

      Mira Sharma answered
      One EDTA (ethylenediaminetetraacetic acid) molecule is required to make an octahedral complex with Ca^2+ ion

      When AgNO3 solution is added in excess to 1 M solution of CoCI3 . xNH3, one mole of AgCI is formed. The value of x is
        Correct answer is '4'. Can you explain this answer?

        Nikita Singh answered
        AgNO3 solution is added in excess of 1 M solution of CoCI3 . xNH3.
        CoCl3​.xNH3​+AgNO3​→AgCl (1mole)
        This precipitation of 1 mol of AgCl by this reaction shows that there is only one Cl outside the coordination sphere, which is not as a ligand ( as ligands are not ionisable).
        Hence, the compound must be as follows:(showing the coordination sphere) [Co(NH3​)4​Cl2​]Cl, as this is the octahedral complex, where it is clear that there are only 2 Cl as ligand and other ligands are NH3​. 
        So, 6−2 = 4 NH3​ ligands.

        Only One Option Correct Type
        Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.
        Q. 
        Primary and secondary valency of Pt in [Pt(en)2CI2] are
        • a)
          + 4 and - 4
        • b)
          + 4 and 6
        • c)
          + 6 and 4
        • d)
          + 2 and 6
        Correct answer is option 'D'. Can you explain this answer?

        Rahul Bansal answered
        The primary valence is its oxidation number, which is +2 in this case (en is uncharged, and the Cl ligands carry a -1 charge each, so Pt must be +2 to balance).
        Secondary valence is coordination number. The en ligand is bidentate, and Cl is monodentate, so you have 2(2) + 2(1) = 6, so the Pt has a coordination number of 6.

        29. A body of mass m1 is moving with velocity u. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system :
        • a)
          increases
        • b)
          decreases but does not become zero
        • c)
          remains same ​
        • d)
          zero
        Correct answer is option 'B'. Can you explain this answer?

        Raghav Bansal answered
        The correct answer is Option B
        Just before the collision the velocity of the center of mass will be

        after the collision if the system moves with velocity V0 then on conserving the momentum
        we will get m1V + 0=(m1 + m2)V0
        or V0 = we can notice that both V0 and u  are the same, due to absence of external force on the system.

        The volume (in mL) of 0.1 M AgNO3 required for complex precipitation of chloride ions present in 30 mL of 0.01 M solution of [Cr(H2O)5Cl]Cl2, as silver chloride is close to
        • a)
          3
        • b)
          4
        • c)
          5
        • d)
          6
        Correct answer is option 'D'. Can you explain this answer?

        Sanchita Reddy answered
        The chemical reaction between them is...[Cr(H2O)5Cl]Cl2 + {2}AgNO3 ——> {2}AgCl(↓) + [Cr(H2O)5Cl]^2+ + {2}NO3-moles of coordinate compound given = molarity x volume(in litre)mole = 0.01 x (30/1000) = (3/10000)for one mole coordinate compound.. we need 2 mole AgNO3....i.e.,1mole complex ===> 2 mole AgNO3(3/10000) mole ==> (2x3/10000) mole AgNO3molarity = moles/volume (in litre)volume(in litre) = mole / molarityV= (6/10000)/0.1 = (0.6) Litrehence volume required = 0.6litre = 6ml

        In the complex Fe(CO)x, the value of x is
        • a)
          3
        • b)
          2
        • c)
          4
        • d)
          5
        Correct answer is option 'D'. Can you explain this answer?

        Maitri Sharma answered
        Complex carbonyls follow Sidwick's EAN rule i.e compound with EAN 36 will be relatively more stable than other metal carbonyls. Iron pentacarbonyl has EAN number of 36 = Z−X+Y = (26−0+2x)
        [Z = atomic number, X = oxidation state of metal, Y= total electrons donated by ligand]
        ∴x = 5. So, the formula will be Fe(CO)5.

        Th e complexes [Co(NH3)6] [Cr (CN)6] and [Cr(NH3)6] [Co(CN)6] are the examples of which type of isomerism? [2011]
        • a)
          Linkage isomerism
        • b)
          Ionization isomerism
        • c)
          Coordination isomerism
        • d)
          Geometrical isomerism
        Correct answer is option 'C'. Can you explain this answer?

        Abhijeet Goyal answered
        Coordination isomerism occurs when cationic and anionic complexes of different metal ions are present in a salt. Interchange of ligand between the complexes give isomers e.g. [Co (NH3)6] [Cr (CN)6]  is an isomer of [Co (CN)6] [Cr (NH3)6]

        30. A body of weight mg is hanging on a string which extends in length by l. The work done in extending the string is :
        • a)
          mgl   
        • b)
          mgl/2   
        • c)
          2 mgl   ​
        • d)
          none of these
        Correct answer is option 'B'. Can you explain this answer?

        Yash Patel answered
        The correct answer is Option A.
        L = h 
        The gravitational force is a conservative field. 
        The work done by the body to extend the string is equivalent to 
        Potential E = mgh = mgL
         

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