Consider the following compounds :
what is the correct sequence of the compound given above in decreasing order of their SN1 reacting ?
  • a)
    I > II > III
  • b)
    III > II > I
  • c)
    II > III > I
  • d)
    III > I > II
Correct answer is option 'B'. Can you explain this answer?
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NEET Question

By sankalp raj · Apr 09, 2019 ·NEET
18 Answers
Akhil George answered Mar 05, 2019

Sneha Jagadeesh answered Apr 23, 2020
Reactivity order for sn1 is stable carbocation
aromatic>non aromatic >anti aromatic this is reactivity order
hence 2nd option is correct

Sunil Jakhar answered May 12, 2020
Phle Br ko hatake C+ banao. fir stability check kro . isme to aromaticity check krne se bhi answer aa jayga . 3>> 2 >>1 Hi hoga answer...

Hakar Patidar answered May 16, 2020

Mandeep Sharma answered Apr 16, 2020
Option b is correct bcz tropollium ion formed being is more stable and the compound I forms antiaromatic i.e. least stable

Abhishek Bmc answered May 23, 2020
Go according to stability of carbocation
aromatic nonaromatic antiaromatic
thus the option

Shyamal Modak. answered May 17, 2020
When carbocation is formed (i) forms anti aromatic compound, (ii) gives non..aromatic and iii gives aromatic compound.
As stability follows the order...aromatic>non-aromatic>anti aromatic. so the order of sn1 is 3>2>1.

Ashok Dhaka answered May 25, 2020
Sn1 reaction stability depends on carbocation stability becoZ intermediate is carbocation. so,in each case we remove halogen (here Br) and form carbocation and see it's stability.
I) if we remove Br then antiaromatic compd form
ll)if we remove Br then non aromatic compd form
lll) if we remove Br then aromatic compd form so,
stability order is lll>ll>l .

Coc Player answered May 01, 2020
IN THIS SN1. FORMATION OF CATION AND ANION
.III IS MORE STABLE THEN II AND AFTER ALL. I.

Pragati Mishra answered Mar 05, 2019
It should be option D i.e. lll>l>ll

Balaram Sahoo answered Apr 14, 2020
As sn1 mechanism occurs through carbocation mechanism so more stable the carbocation more give reaction as 3rd is more stable than 1st it is aromatic but 1st is non aromatics

Suman Singha answered May 25, 2020
Answer will be B

Prabhat Singh answered Apr 09, 2019
Make carbonation 1st And check stability of C^+, ...In 1st antiaromatic ..In 2nd non aromatic..nd in 3(tropolium) aromatic carbocation..so answer is 2

Gulzar Ahmad answered May 25, 2020
In SN 1 rxns,carbocation is formed as an intermediate....On removing Br- ion from all the three compounds,carbocation is formed.... compound 3 becomes aromatic,hence is more stable....Between 1 nd 2,two is more stable bcoz it is non-aromatic while the ist one is anti-aromatic .... since non-aromatic is more stable than anti-aromatic aromatic, hence option B is correct

Dileep Ravula answered Apr 27, 2020
Based on stability of carbocation the correct anwser is b

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