A deuteron has an energy 4Mev when accelerated through a potential dif...
Answer
Option 3) 12Mev
Explanation
The energy of a particle accelerated by a potential difference is given by the equation:
Energy (E) = Potential Difference (V) x Charge (q)
Since the charge of a deuteron is twice that of a proton, the energy of a deuteron accelerated by a potential difference (V) can be given by:
E = 2qV
Given that the energy of a deuteron is 4Mev when accelerated through a potential difference (V), we can write:
4Mev = 2qV
Therefore, the potential difference (V) can be expressed as:
V = 2Mev/q
Now, if a particle with the same charge as the deuteron is accelerated through the same potential difference (V), its energy can be given by:
E = qV
Substituting the value of V from above, we get:
E = q x (2Mev/q) = 2Mev
Since the charge of the particle is the same as the deuteron, its energy will be half of that of the deuteron, which is 4Mev. Therefore, the correct option is 3) 12Mev, which is three times the energy of the deuteron.