Sodium hydroxide (NaOH) is a strong base, and aluminum oxide (Al2O3) is an amphoteric oxide, meaning it can react with both acids and bases. When sodium hydroxide acts on aluminum oxide, a reaction occurs to form a new compound.

The balanced chemical equation for the reaction between sodium hydroxide and aluminum oxide is as follows:

2NaOH + Al2O3 → 2NaAlO2 + H2O

In this reaction, two moles of sodium hydroxide react with one mole of aluminum oxide to produce two moles of sodium aluminate (NaAlO2) and one mole of water (H2O).

Let's analyze the options given and determine the correct product:

a) NaAlO3: This compound is not formed in the reaction between sodium hydroxide and aluminum oxide. It is the formula for sodium metaaluminate, which is formed when sodium hydroxide reacts with aluminum metal.

b) Na3Al2O6: This compound is not formed in the reaction between sodium hydroxide and aluminum oxide. It is the formula for sodium hexaaluminate, which is formed when sodium hydroxide reacts with aluminum hydroxide.

c) NaAlO2: This is the correct compound formed in the reaction between sodium hydroxide and aluminum oxide. It is known as sodium aluminate and has a 1:1 ratio of sodium to aluminum.

d) NaAl2O3: This compound is not formed in the reaction between sodium hydroxide and aluminum oxide. It is the formula for sodium trioxoaluminate, which is formed when sodium hydroxide reacts with aluminum metal oxide.

In conclusion, when sodium hydroxide acts on aluminum oxide, the correct product formed is sodium aluminate (NaAlO2), option c.

Al2O3 + 2NaOH → 2NaAlO2 + H2O

Aluminium oxide + Sodium hydoxide = Sodium aluminate + Water