2 cm long object is placed before a convex lens of 10cm focal length a...
Problem Statement:
A 2 cm long object is placed before a convex lens of 10cm focal length at a distance of 15cm in perpendicular to the optic axis. What will be the position and size of the image formed?
Solution:
Given Data:
- Length of the object, h = 2cm
- Focal length of the convex lens, f = 10cm
- Distance between the object and the lens, u = -15cm (Since the object is placed before the lens, u will be negative)
Formula used:
The formula used to calculate the position and size of the image formed is:
1/f = 1/v - 1/u
where,
f = focal length of the convex lens
u = object distance from the lens
v = image distance from the lens
The magnification of the image is given by:
m = -v/u
Calculation:
Substituting the given values in the formula, we get:
1/10 = 1/v - 1/-15
v = 30cm
The magnification of the image is given by:
m = -v/u
m = -30/-15
m = 2
The negative sign in the magnification indicates that the image formed is inverted with respect to the object.
Answer:
The position of the image is 30 cm from the convex lens and the magnification of the image is 2. Therefore, the size of the image formed will be twice the size of the object.