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A2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the krus is 15 cm. Find the nature, position and size of the image. Also find its magnification.?
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A2.0 cm tall object is placed perpendicular to the principal axis of a...
Given Data
- Height of the object (h) = 2.0 cm
- Focal length of the convex lens (f) = 10 cm
- Object distance from the lens (u) = -15 cm (considering the sign convention)
Image Formation Using Lens Formula
The lens formula is given by:
1/f = 1/v - 1/u
Where:
- v = image distance (to be calculated)
Substituting the values:
1/10 = 1/v + 1/15
Calculating Image Distance
- Rearranging gives:
1/v = 1/10 + 1/15
- Finding a common denominator (30):
1/v = (3 + 2) / 30 = 5/30
- Therefore, v = 6 cm
Nature and Position of the Image
- The image distance (v) is positive, indicating that the image is real and located on the opposite side of the lens.
- The image is formed at a distance of 6 cm from the lens.
Size of the Image
To find the size of the image (h'):
h' = (v/u) * h
Substituting the values:
h' = (6/-15) * 2.0 = -0.8 cm
Characteristics of the Image
- The negative sign indicates that the image is inverted.
- Height of the image = 0.8 cm (inverted)
Magnification Calculation
Magnification (m) is given by:
m = h'/h = -0.8/2.0 = -0.4
Final Summary
- Nature: Real and inverted
- Position: 6 cm from the lens
- Size: 0.8 cm (inverted)
- Magnification: -0.4
This analysis provides a comprehensive understanding of the image formed by the convex lens based on the given parameters.
- Height of the object (h) = 2.0 cm
- Focal length of the convex lens (f) = 10 cm
- Object distance from the lens (u) = -15 cm (considering the sign convention)
Image Formation Using Lens Formula
The lens formula is given by:
1/f = 1/v - 1/u
Where:
- v = image distance (to be calculated)
Substituting the values:
1/10 = 1/v + 1/15
Calculating Image Distance
- Rearranging gives:
1/v = 1/10 + 1/15
- Finding a common denominator (30):
1/v = (3 + 2) / 30 = 5/30
- Therefore, v = 6 cm
Nature and Position of the Image
- The image distance (v) is positive, indicating that the image is real and located on the opposite side of the lens.
- The image is formed at a distance of 6 cm from the lens.
Size of the Image
To find the size of the image (h'):
h' = (v/u) * h
Substituting the values:
h' = (6/-15) * 2.0 = -0.8 cm
Characteristics of the Image
- The negative sign indicates that the image is inverted.
- Height of the image = 0.8 cm (inverted)
Magnification Calculation
Magnification (m) is given by:
m = h'/h = -0.8/2.0 = -0.4
Final Summary
- Nature: Real and inverted
- Position: 6 cm from the lens
- Size: 0.8 cm (inverted)
- Magnification: -0.4
This analysis provides a comprehensive understanding of the image formed by the convex lens based on the given parameters.
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A2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the krus is 15 cm. Find the nature, position and size of the image. Also find its magnification.?
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A2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the krus is 15 cm. Find the nature, position and size of the image. Also find its magnification.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the krus is 15 cm. Find the nature, position and size of the image. Also find its magnification.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the krus is 15 cm. Find the nature, position and size of the image. Also find its magnification.?.
A2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the krus is 15 cm. Find the nature, position and size of the image. Also find its magnification.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the krus is 15 cm. Find the nature, position and size of the image. Also find its magnification.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the krus is 15 cm. Find the nature, position and size of the image. Also find its magnification.?.
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