• Height of the object (h) = 5 cm


• Distance of the object from the lens (u) = 30 cm


• Focal length of convex lens (f) = 20 cm

Using the lens formula, we can find the position of the image formed by the convex lens.

1/f = 1/v - 1/u

Here, f = 20 cm and u = 30 cm

1/20 = 1/v - 1/30

1/v = 1/20 + 1/30

1/v = 1/12

v = 12 cm

Therefore, the position of the image formed by the convex lens is 12 cm.



To find the nature of the image formed by the convex lens, we use the magnification formula.

Magnification (m) = Height of the image (h') / Height of the object (h) = -v / u

Here, h = 5 cm, u = 30 cm and v = 12 cm

m = - (12/30) = - 0.4

Since the magnification is negative, the image formed is inverted.



We can use the magnification formula to find the size of the image formed by the convex lens.

Magnification (m) = Height of the image (h') / Height of the object (h)

Here, h = 5 cm and m = -0.4

h' / 5 = -0.4

h' = -2 cm

Since the height of the image is negative, the image formed is virtual and erect and its size is 2 cm.



When an object is placed perpendicular to the principal axis of a convex lens, an image is formed on the other side of the lens. The position of the image can be found using the lens formula, which relates the object distance, image distance, and focal length of the lens. The nature of the image can be determined using the magnification formula, which relates the height of the image and the height of the object. If the magnification is negative, the image formed is inverted. The size of the image can also be found using the magnification formula. If the height of the image is negative, the image formed is virtual and erect. In this case, the height of the image is 2 cm, which means that the image is smaller than the object.