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A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)
- a)75 m/s
- b)55 m/s
- c)40 m/s
- d)60 m/s
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A ball is dropped from a high rise platform at t = 0 starting from res...
Clearly distance moved by 1st bal l in 18s = distance moved by 2nd ball in 12s.
Now, distance moved in 18 s by 1st
Now, distance moved in 18 s by 1st
= 90 x 18 = 1620 m
Distance moved in 12s by 2nd ball
∴ 1620 = 12 v + 5 x 144
⇒ v = 135 – 60 = 75 ms –1
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A ball is dropped from a high rise platform at t = 0 starting from res...
Given data:
- A ball is dropped from a high rise platform at t = 0 starting from rest.
- After 6 seconds another ball is thrown downwards from the same platform with a speed v.
- The two balls meet at t = 18s.
- g = 10 m/s^2
To find: value of v
Solution:
1. Let's consider the motion of the first ball (dropped from rest):
- Using the equation s = ut + 1/2 at^2, we can find the distance covered by the first ball in 18 seconds.
- Here, u = 0, a = g = 10 m/s^2, t = 18 s
- s = 0 + 1/2 * 10 * (18)^2
- s = 1620 m
- So, the first ball covers a distance of 1620 m in 18 seconds.
2. Now, let's consider the motion of the second ball (thrown downwards with speed v):
- Let's assume that the second ball covers the same distance as the first ball in 18 seconds.
- So, using the equation s = ut + 1/2 at^2, we can find the acceleration of the second ball.
- Here, s = 1620 m, u = v, a = g = 10 m/s^2, t = 12 s (as the second ball was thrown after 6 seconds)
- 1620 = v * 12 + 1/2 * 10 * (12)^2
- 1620 = 12v + 720
- 12v = 900
- v = 75 m/s
Therefore, the value of v is 75 m/s.
Answer: (a) 75 m/s
- A ball is dropped from a high rise platform at t = 0 starting from rest.
- After 6 seconds another ball is thrown downwards from the same platform with a speed v.
- The two balls meet at t = 18s.
- g = 10 m/s^2
To find: value of v
Solution:
1. Let's consider the motion of the first ball (dropped from rest):
- Using the equation s = ut + 1/2 at^2, we can find the distance covered by the first ball in 18 seconds.
- Here, u = 0, a = g = 10 m/s^2, t = 18 s
- s = 0 + 1/2 * 10 * (18)^2
- s = 1620 m
- So, the first ball covers a distance of 1620 m in 18 seconds.
2. Now, let's consider the motion of the second ball (thrown downwards with speed v):
- Let's assume that the second ball covers the same distance as the first ball in 18 seconds.
- So, using the equation s = ut + 1/2 at^2, we can find the acceleration of the second ball.
- Here, s = 1620 m, u = v, a = g = 10 m/s^2, t = 12 s (as the second ball was thrown after 6 seconds)
- 1620 = v * 12 + 1/2 * 10 * (12)^2
- 1620 = 12v + 720
- 12v = 900
- v = 75 m/s
Therefore, the value of v is 75 m/s.
Answer: (a) 75 m/s
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A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)a)75 m/sb)55 m/sc)40 m/sd)60 m/sCorrect answer is option 'A'. Can you explain this answer?
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A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)a)75 m/sb)55 m/sc)40 m/sd)60 m/sCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)a)75 m/sb)55 m/sc)40 m/sd)60 m/sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)a)75 m/sb)55 m/sc)40 m/sd)60 m/sCorrect answer is option 'A'. Can you explain this answer?.
A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)a)75 m/sb)55 m/sc)40 m/sd)60 m/sCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)a)75 m/sb)55 m/sc)40 m/sd)60 m/sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)a)75 m/sb)55 m/sc)40 m/sd)60 m/sCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18s.What is the value of v? [2010] (take g = 10 m/s2)a)75 m/sb)55 m/sc)40 m/sd)60 m/sCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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