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A ball is dropped from a high rise platform at 1 = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18 s. What is the value of v?
(Take g = 10m∕s2)
- a)75 m/s
- b)55 m/s
- c)40 m/s
- d)60 m/s
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A ball is dropped from a high rise platform at 1 = 0 starting from re...
Let the two balls meet after t s at distance x from the platform.
For the first ball u = 0, t = 18s, g = 10m∕s2
For second ball u = v, t = 12s, g = 10m∕s2
From equations (i) and (ii), we get
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Community Answer
A ball is dropped from a high rise platform at 1 = 0 starting from re...
Given data:
- Initial velocity of the first ball (u1) = 0 m/s
- Time when the second ball is thrown (t) = 6 s
- Time when the two balls meet (t) = 18 s
- Acceleration due to gravity (g) = 10 m/s^2
Calculating the distance covered by the first ball:
- Using the formula s = ut + 0.5at^2, where s is the distance covered, u is the initial velocity, a is the acceleration, and t is the time.
- For the first ball, s1 = 0*6 + 0.5*10*6^2 = 180 m
Calculating the distance covered by the second ball:
- The second ball is thrown with a velocity v after 6 seconds.
- Let d be the distance covered by the second ball before the two balls meet.
- For the second ball, d = 6v + 0.5*10*(18-6)^2 = 6v + 720
Equating the distances covered by both balls:
- Since the two balls meet at t = 18 s, the distances covered by both balls should be equal.
- Therefore, 180 = 6v + 720
- Solving for v, we get v = (180 - 720)/6 = -540/6 = -90 m/s
Conclusion:
- The negative sign indicates that the second ball is thrown downwards, so the magnitude of the velocity is 90 m/s.
- However, since speed is a scalar quantity, the magnitude of the velocity is 90 m/s.
- Therefore, the value of v is 90 m/s.
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A ball is dropped from a high rise platform at 1 = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18 s. What is the value of v?(Take g = 10m∕s2)a)75 m/sb)55 m/sc)40 m/sd)60 m/sCorrect answer is option 'A'. Can you explain this answer?
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