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2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3?
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2 mole of PCl5 were introduced in a vessel of 5 L capacity of a partic...
Solution:
Given:
- Number of moles of PCl5 introduced = 2 mol
- Volume of the vessel = 5 L
- % dissociation of PCl5 at equilibrium = 35%
To Find:
- Value of Kc for the reaction
Explanation:
The balanced chemical equation for the dissociation of PCl5 is:
PCl5 ⇌ PCl3 + Cl2
The equilibrium constant Kc for the reaction is given by the expression:
Kc = ([PCl3] x [Cl2])/[PCl5]
At equilibrium, let the concentration of PCl5 that remains undissociated be x mol/L. Then, the concentration of PCl3 and Cl2 that are produced will be x mol/L each.
The concentration of PCl5 that dissociates is (2-x) mol/L. Therefore, the concentrations of PCl3 and Cl2 that are produced are also (2-x) mol/L each.
Using the given percentage of dissociation (35%), we can write:
(2-x)/2 x 100 = 35
Solving for x, we get:
x = 1.3 mol/L
Therefore, at equilibrium:
[PCl5] = 1.3 mol/L
[PCl3] = [Cl2] = (2 - 1.3) mol/L = 0.7 mol/L
Substituting these values in the expression for Kc, we get:
Kc = ([PCl3] x [Cl2])/[PCl5]
= (0.7 x 0.7)/1.3
= 0.377
Therefore, the value of Kc for the reaction is 0.377, which is option (b).
Answer:
The value of Kc for the reaction PCl5 ⇌ PCl3 + Cl2 is 0.377.
Given:
- Number of moles of PCl5 introduced = 2 mol
- Volume of the vessel = 5 L
- % dissociation of PCl5 at equilibrium = 35%
To Find:
- Value of Kc for the reaction
Explanation:
The balanced chemical equation for the dissociation of PCl5 is:
PCl5 ⇌ PCl3 + Cl2
The equilibrium constant Kc for the reaction is given by the expression:
Kc = ([PCl3] x [Cl2])/[PCl5]
At equilibrium, let the concentration of PCl5 that remains undissociated be x mol/L. Then, the concentration of PCl3 and Cl2 that are produced will be x mol/L each.
The concentration of PCl5 that dissociates is (2-x) mol/L. Therefore, the concentrations of PCl3 and Cl2 that are produced are also (2-x) mol/L each.
Using the given percentage of dissociation (35%), we can write:
(2-x)/2 x 100 = 35
Solving for x, we get:
x = 1.3 mol/L
Therefore, at equilibrium:
[PCl5] = 1.3 mol/L
[PCl3] = [Cl2] = (2 - 1.3) mol/L = 0.7 mol/L
Substituting these values in the expression for Kc, we get:
Kc = ([PCl3] x [Cl2])/[PCl5]
= (0.7 x 0.7)/1.3
= 0.377
Therefore, the value of Kc for the reaction is 0.377, which is option (b).
Answer:
The value of Kc for the reaction PCl5 ⇌ PCl3 + Cl2 is 0.377.
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2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3?
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2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3?.
2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3?.
Solutions for 2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3? in English & in Hindi are available as part of our courses for NEET.
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2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3?, a detailed solution for 2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3? has been provided alongside types of 2 mole of PCl5 were introduced in a vessel of 5 L capacity of a particular temperature . At equilibrium PCl5 was found to be 35%dissociated . The value of kc for the reaction . PCl3 PCl2 -----PCl5 a. 1.89 b. 0.377. c. 1.33. d. 13.3? theory, EduRev gives you an
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