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What is the pressure of mixture of 1 g of dihydrogen & 1.4 g of dinitrogen stored in 5 litre vessel at 127degree celsius?
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What is the pressure of mixture of 1 g of dihydrogen & 1.4 g of dinitr...
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What is the pressure of mixture of 1 g of dihydrogen & 1.4 g of dinitr...
To calculate the pressure of a mixture of dihydrogen (H2), we need to use the ideal gas law equation:

PV = nRT

Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature

First, we need to determine the number of moles of dihydrogen (H2) in 1 g. For this, we need to know the molar mass of dihydrogen, which is 2 g/mol.

n = mass / molar mass
n = 1 g / 2 g/mol
n = 0.5 mol

Now, let's assume the volume and temperature are constant.

V = constant
T = constant

We can rewrite the equation as:

P = nRT / V

Since V and T are constant, we can simplify the equation to:

P = (nR / V) * T

Now, let's substitute the known values:

n = 0.5 mol
R = 0.0821 L·atm/(mol·K) (ideal gas constant)
V = constant (unknown)
T = constant (unknown)

We can't determine the pressure without knowing the values of V (volume) and T (temperature).
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What is the pressure of mixture of 1 g of dihydrogen & 1.4 g of dinitrogen stored in 5 litre vessel at 127degree celsius?
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