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1 mole of N₂ and 2 moles of H₂ are allowed to react in a 1 dm3 vessel. At equilibrium 0.8 mole of NH₃ is formed. The concentration of H₂ in the vessel is
  • a)
    0.6 mole
  • b)
    0.8 mole
  • c)
    0.2 mole
  • d)
    0.4 mole
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
1 mole of N₂ and 2 moles of H₂ are allowed to react in a 1...
Given:
- 1 mole of N
- 2 moles of H
- 0.8 mole of NH formed at equilibrium

To find:
- Concentration of H in the vessel

Solution:
The balanced chemical equation for the reaction is:

N2(g) + 3H2(g) ⇌ 2NH3(g)

From the equation, we can see that:
- 1 mole of N reacts with 3 moles of H
- 2 moles of H react with 2/3 mole of N

Let x be the number of moles of H that reacted to form 0.8 mole of NH. Then, we have:

- 0.8 mole of NH formed from x mole of H
- 1 mole of N reacted with 3x/2 moles of H

At equilibrium, the number of moles of each substance present in the vessel can be calculated using the following table:

Substance | Initial moles | Change | Equilibrium moles
--- | --- | --- | ---
N2 | 1 | -1(3x/2) | 1-3x/2
H2 | 2 | -x | 2-x
NH3 | 0 | +0.8 | 0.8

Using the law of chemical equilibrium, we can write:

Kc = [NH3]^2/([N2][H2]^3)

At equilibrium, we have:

Kc = (0.8)^2/[(1-3x/2)(2-x)^3]

Simplifying the expression, we get:

Kc = 0.1067/(1.125-6.375x+10.125x^2-6x^3+x^4)

Assuming that x is small compared to 2, we can neglect the terms containing x^2 and x^3. Then, we have:

Kc ≈ 0.1067/(1.125-6.375x+x^4)

At equilibrium, the concentration of NH3 is 0.8/1 = 0.8 M. Using the stoichiometry of the reaction, we can write:

[H2] = (2-x)/1 = 2-x M

Plugging in these values into the expression for Kc, we get:

0.1067 = (0.8)^2/[(1-3x/2)(2-x)^3]

Solving for x, we get:

x = 0.4

Therefore, the concentration of H in the vessel is:

[H2] = 2-x = 2-0.4 = 1.6 M

Answer: Option B. 0.8 mole
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1 mole of N₂ and 2 moles of H₂ are allowed to react in a 1...
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1 mole of N₂ and 2 moles of H₂ are allowed to react in a 1 dm3 vessel. At equilibrium 0.8 mole of NH₃ is formed. The concentration of H₂ in the vessel isa)0.6 moleb)0.8 molec)0.2 moled)0.4 moleCorrect answer is option 'B'. Can you explain this answer?
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