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In a chemical equilibrium a + c gives c + D1 1 mole of each of the two react in the mix 0.4 mole each of the product are formed the equilibrium constant?
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In a chemical equilibrium a + c gives c + D1 1 mole of each of the two...
Understanding Chemical Equilibrium
Chemical equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction, resulting in constant concentrations of reactants and products.
Equilibrium Reaction
- The given reaction is:
A + C ⇌ C + D1
Initial Concentrations
- Initially, there is 1 mole of A and 1 mole of C.
- Therefore, the initial concentrations are:
- [A] = 1 mole
- [C] = 1 mole
- [D1] = 0 moles
Formation of Products
- It is stated that 0.4 moles of products are formed at equilibrium.
- Hence, at equilibrium:
- [C] = Initial C - Reacted C + Formed C = 1 - 0.4 + 0.4 = 1 mole
- [D1] = 0 + 0.4 = 0.4 moles
Equilibrium Concentrations
- At equilibrium, the concentrations are:
- [A] = 1 - 0.4 = 0.6 moles
- [C] = 1 moles
- [D1] = 0.4 moles
Calculating the Equilibrium Constant (Kc)
- The equilibrium constant (Kc) is expressed as:
Kc = [C][D1] / [A]
- Substituting the equilibrium concentrations:
Kc = (1)(0.4) / (0.6)
Final Calculation
- Kc = 0.4 / 0.6 = 0.67
Conclusion
- The equilibrium constant (Kc) for the reaction A + C ⇌ C + D1 at equilibrium is approximately 0.67. This value indicates the ratio of products to reactants at equilibrium, providing insights into the extent of the reaction.
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In a chemical equilibrium a + c gives c + D1 1 mole of each of the two react in the mix 0.4 mole each of the product are formed the equilibrium constant?
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